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MAXImum [283]
3 years ago
7

A 6.5×10−2 kg arrow hits the target at 25 m/s and penetrates 3.8 cm before stopping.

Physics
1 answer:
White raven [17]3 years ago
8 0
1) We use:
2as = v² - u², with v = 0,
to find the acceleration of the arrow.
2 x 0.038 x a = -(25)²
a = -8.22 x 10³ m/s²
F = ma
F = 6.5 x 10⁻² x -8.22 x 10³ 
F = -534.2 N; the negative direction indicates that the force is in the opposite direction of the motion.

B) The arrows force is the same but in the opposite directioin.
534.2 N

C) a = -8.22 x 10³ m/s²
s = -(65)²/(2 x -8.22 x 10³)
s = 25.7 cm
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