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3 years ago

5. A ball is sitting at rest on the floor. What will happen if a balanced force is applied to the ball? *

Physics

1 answer:

Leno4ka [110]3 years ago

3 0

When the balanced force is applied on the ball It will roll away from the force.

Explanation:

A ball lies on the floor in rest. If the balanced force is applied to

the ball, the force will push away.

The forces would include gravity and the forces of air particles entering the ball from almost all directions.
And the ground is exercising the force and shifting away from the impact.

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A man can throw a ball a maximum horizontal distance of 56.1523 m. The acceleration of gravity is 9.8 m/s 2 . How far can he thr

IceJOKER [234]

Answer:

hmax= 28.2 m

Explanation:

Horizontal movement:

For the horizontal movement, as once released, nothing exerts any influence on the ball in the horizontal direction, it will keep moving at a constant speed, so, the equation for the horizontal displacement is as follows:

x = v₀*t = 56.1523 m

Vertical movement:

For the vertical movement, once thrown upward, the ball is under the sole influence of gravity, g, which causes the ball to accelerate downward, and which magnitude is 9.8 m/s².
At any time, applying the definition of acceleration, we can find the value of the velocity, as follows:

$vf = vo-g*t$

When the ball reaches to the maximum height, the ball will come momentarily at rest, so vf =0.
At this point, we can find the time at which the ball reached to its highest point, as follows:

$t = \frac{vo}{g}$

In the same way, we can find the maximum height reached by the ball, just replacing this value of time in the equation for the displacement, in the vertical direction, as follows:

$h = vo*t -\frac{1}{2} *g*t^{2}$

$hmax = vo*(\frac{vo}{g}) -\frac{1}{2} *g*(\frac{vo}{g} )^{2} =\frac{vo^{2}}{2*g}$

Now, returning to the horizontal movement, as the time must be the same for both movements, we can replace the value for time we have just found, in the equation for the horizontal displacement:

$x = v0x * t = v0x* \frac{voy}{g}$

But as we know that vox = voy, we can rewrite the equation above as follows:

$x = v0* t = v0* \frac{vo}{g} =\frac{vo^{2} }{g} = 56.1523 m$

We can solve for v₀, as follows:

$vo = \sqrt{56.1523 m *9.8 m/s2} =23.5 m/s$

Now, we can replace this value in the expression for hmax, as follows:
$hmax = \frac{vo^{2}}{2*g} =\frac{(23.5m/s)^{2}}{2*9.8 m/s2} = 28.2 m$

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3 years ago

The strength of an electrical field decreases as you move farther from the source. True or False

slamgirl [31]

It is True it decreases

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2 years ago

Read 2 more answers

A space station, in the form of a spoked wheel 120 m in diameter, rotates to provide an artificial gravity of 3.00 m/s² for pers

lubasha [3.4K]

Answer:

2.12 rpm

Explanation:

$a_c= Centripetal\ acceleration=3.00\ m/s^2\\r=radius=\frac {120}{2}=60\ m\\a_c=\frac {v^2}{r}\\\Rightarrow v^2=a_c\times r\\\Rightarrow v^2=3\times 60=180\\\Rightarrow v=\sqrt{180}=13.41\ m/s\\$

$v=\omega r\\\Rightarrow \omega=\frac {v}{r}\\\Rightarrow \omega=\frac {13.41}{60}\\\Rightarrow \omega=0.2236\ rad/s\\1\ rad/s=9.55\ rpm\\\Rightarrow 0.2236\ rad/s=2.12\ rpm\\\therefore Wheel\ rotations=2.12\ rpm$

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3 years ago

Thermopane window is constructed, using two layers of glass 4.0 mm thick, separated by an air space of 5.0 mm.

Bond [772]

To solve this problem it is necessary to apply the concepts related to rate of thermal conduction

$\frac{Q}{t} = \frac{kA\Delta T}{d}$

The letter Q represents the amount of heat transferred in a time t, k is the thermal conductivity constant for the material, A is the cross sectional area of the material transferring heat, $\Delta T$ , T is the difference in temperature between one side of the material and the other, and d is the thickness of the material.