Answer:
{
x
∣
x
>
1
} or x
∈
(
1
,
∞
)
Step-by-step explanation:
2
x
+
3
>
7
⇒
2
x
>
4
(subtract 3 from both sides)
2
x
+
3
>
7
⇒
x
>
2
(divide both sides by 2)
2
x
+
9
>
11
⇒ 2
x
>
2
(subtract 9 from both sides)
2
x
+
9
>
11
⇒
x
>
1
(divide both sides by 2)
if an x
-value is greater than 2, it will automatically be greater than 1. Thus, the solution set for 2
x+
3
>
7 is a subset of the one for 2
x
+
9
>11
.That means, all we need to do here is list the solution set for 2
x
+
9
>
11
, and we're done.
The solution set we need is simply "all x such that x is greater than 1", or {
x
∣
x
>
1
}
or
x
∈
(
1
,
∞
)
It's prob, It's kind of is the top left a SIx OR ZERO?!
Step-by-step explanation:
it will help u
Answer: k = -10
Step-by-step explanation:
-4 = k + 6
-4 - 6 = k
-10 = k
Answer:
yeh you are correct so it will be b is equal to minus 42 minus 9.3 that will be equal to -51.3 so that is the value of b