The triangles that would be created if the rectangle has a length and width that are different is a right scalene triangle.
It will have one right angle and all three sides of the triangle will be different lengths because the hypotenuse (the diagonal will be longer than the other two sides.
Answer:
x ≥4
Step-by-step explanation:
-4(8-3x) ≥6x-8
Distribute
-32+12x ≥6x-8
Subtract 6x from each side
-32+12x-6x ≥6x-6x-8
-32+6x ≥-8
Add 32 from each side
-32+32 +6x ≥-8+32
6x ≥ 24
Divide each side by 6
6x/6 ≥24/6
x ≥4
Answer:
9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;
(x - 2)²/2² - (y + 3)²/3² = 1
Step-by-step explanation:
The standard form of a hyperbola is given as follows;
(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1
The given equation is presented as follows;
9·x² - 36·x = 4·y² + 24·y + 36
By completing the square, we get;
(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)
(3·x - 6)² - 36 = (2·y + 6)²
(3·x - 6)² - (2·y + 6)² = 36
(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1
(3·x - 6)²/6² - (2·y + 6)²/6² = 1
3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1
(x - 2)²/2² - (y + 3)²/3² = 1
The equation of the hyperbola is (x - 2)²/2² - (y + 3)²/3² = 1.
Answer:
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Step-by-step explanation:
