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faltersainse [42]
3 years ago
9

GUYS PLEASE HELP: Evaluate the function f (x) = 2x+6 for: f(-19) =

Mathematics
2 answers:
Mariulka [41]3 years ago
3 0

Answer:

-32

Step-by-step explanation:

f(x) = 2x + 6

f(-19) = 2*(-19) + 6

        = -38 + 6

        = -32

NeX [460]3 years ago
3 0

Answer:

-32

Step-by-step explanation:

f(x) = 2x + 6

f(-19) = 2*(-19) + 6

       = -38 + 6

       = -32

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4 question in one 65 points
jeka94

Q6.

The slope-intercept form: y = mx + b

m - slope

b - y-intercept

We have: slope m = 3, y-intercept (0, 4) → b= 4

<h3>Answer: y = 3x + 4</h3>

Q7.

2x + 4y = 4     |subtract 2x from both sides

4y = -2x + 4     |divide both sides by 4

y = -0.5x + 1

Only second graph has y-intercept = 1.

<h3>Answer: The second graph.</h3>

Q8.

The point-slope form:

y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}

We have

(-16,\ 8)\to x_1=-16,\ y_1=8\\(4,\ -2)\to x_2=4,\ y_2=-2

Substitute:

m=\dfrac{-2-8}{4-(-16)}=\dfrac{-10}{20}=-\dfrac{1}{2}\\\\y-8=-\dfrac{1}{2}(x-(-16))\\\\y-8=-\dfrac{1}{2}(x+16)

<h3>Answer: The first equation.</h3>

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It's a vertical line. The equation of a vertical line is x = <em>a</em>, where <em>a</em> is any real number.

<h3>Answer: x = -4</h3>
6 0
3 years ago
Read 2 more answers
Please help me with question 26
AleksAgata [21]
Answer: B) 65 degrees

-----------------------------------------------------

angle AEB = angle GEC
5x = 3x+10
5x-3x = 10
2x = 10
x = 5

angle GEC = 3x+10
angle GEC = 3*5+10
angle GEC = 25 degrees

Angle FEG = 90 - (angle GEC)
Angle FEG = 90 - 25
Angle FEG = 65 degrees

5 0
3 years ago
School pennants cost $18 each. Ms.Lee says she will pay $146 for 7 pennants. Is her answer reasonable?
crimeas [40]

Well, all we have to do to figure out if Ms. Lee’s offer is reasonable is multiply the unit price ($18) by 7

18 x 7 = 126

Since she offered $146, she could actually purchase 8 pennants for $144

Therefore, her answer wouldn’t be reasonable

Hope this helps you

Brainliest would be appreciated!

-AaronWiseIsBae

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3 years ago
F(x) = 4√(2x³-1)<br> F'(x) =.....?
goldfiish [28.3K]

Answer:

\large\boxed{f'(x)=\dfrac{12x^2}{\sqrt{2x^3-1}}}

Step-by-step explanation:

f(x)=4\sqrt{2x^3-1}=4\left(2x^3-1\right)^\frac{1}{2}\\\\f'(x)=4\cdot\dfrac{1}{2}(2x^3-1)^{-\frac{1}{2}}\cdot3\cdot2x^2=\dfrac{12x^2}{(2x^3-1)^\frac{1}{2}}=\dfrac{12x^2}{\sqrt{2x^3-1}}\\\\\text{used}\\\\\sqrt{a}=a^\frac{1}{2}\\\\\bigg[f\left(g(x)\right)\bigg]'=f'(g(x))\cdot g'(x)\\\\\bigg[nf(x)\bigg]'=nf'(x)\\\\(x^n)'=nx^{n-1}

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3 years ago
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elena-14-01-66 [18.8K]

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