Answer:
A ∩ B = {1, 3, 5}
A - B = {2, 4}
Step-by-step explanation:
The given problem regards sets and set notation, a set can simply be defined as a collection of values. One is given the following information:
A = {1, 2, 3, 4, 5}
B = {1, 3, 5, 6, 9}
One is asked to find the following:
A ∩ B,
A - B
1. Solving problem 1
A ∩ B,
The symbol (∩) in set notation refers to the intersection between the two sets. It essentially asks one to find all of the terms that two sets have in common. The given sets (A) and (B) have the values ({1, 3, 5}) in common thus, the following statement can be made,
A ∩ B = {1, 3, 5}
2. Solving problem 2
A - B
Subtracting two sets is essentially taking one set, and removing the values that are shared in common with the other set. Sets (A) and (B) have the following values in common ({1, 3, 5}). Thus, when doing (A - B), one will omit the values ({1, 3, 5}) from set (A).
A - B = {2, 4}
1 1/9
To figure out how much walnuts to a pound of dried fruit you’d need to do proportions. So we cross multiply:
2/3 = X
—————- —————-
3/5 = 1
You multiply diagnols 2/3 x 1 = 2/3
3/5 times x is 3/5x.
2/3 = 3/5x. Isolate the variable. Divide 3/5 on both sides cancel out 3/5. 2/3 divide by 3/5 is 2/3 x 5/3 which is 10/9 which equals 1 1/9.
So for 1 lb of dried fruit you need 1 1/9 lb of walnuts to maintain the same mixture
To evaluate two fractions being divided, you must turn the right fraction into a reciprocal. That means you must put the bottom number at the top and then put the top number on the bottom (you’re basically switching them).
8/13 / 3/2
Now, once you turned the other number into a reciprocal, you multiply across. The top number times the other top number and do this to the bottom numbers, too.
8/13 * 3/2 = 24/26
You found the answer, 24/26. But as you can see, it’s not one of the choices. That’s because you need to simplify.
24/26 / 2/2 = 12/13
12/13 is your answer, or choice C!
I hope this helped. Comment below if you have any questions.
Answer:
The radius is 25 in., circumference is 207
Step-by-step explanation:
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Have a nice day.
We have to solve this equation:
Third degree polynomials like this one are not easily solved, but this one has a root at x = 0. The let us factorize this polynomial as x times a second degree polynomial:
Now we can find the roots of the quadratic polynomial as:
![\begin{gathered} x=\frac{-(-6)\pm\sqrt[]{(-6)^2-4\cdot1\cdot6}}{2\cdot1} \\ x=\frac{6\pm\sqrt[]{36-24}}{2} \\ x=\frac{6\pm\sqrt[]{12}}{2} \\ x=\frac{6\pm\sqrt[]{4\cdot3}}{2} \\ x=\frac{6\pm2\sqrt[]{3}}{2} \\ x=3\pm\sqrt[]{3} \\ x_1=3-\sqrt[]{3} \\ x_2=3+\sqrt[]{3} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-%28-6%29%5Cpm%5Csqrt%5B%5D%7B%28-6%29%5E2-4%5Ccdot1%5Ccdot6%7D%7D%7B2%5Ccdot1%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B36-24%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B12%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm%5Csqrt%5B%5D%7B4%5Ccdot3%7D%7D%7B2%7D%20%5C%5C%20x%3D%5Cfrac%7B6%5Cpm2%5Csqrt%5B%5D%7B3%7D%7D%7B2%7D%20%5C%5C%20x%3D3%5Cpm%5Csqrt%5B%5D%7B3%7D%20%5C%5C%20x_1%3D3-%5Csqrt%5B%5D%7B3%7D%20%5C%5C%20x_2%3D3%2B%5Csqrt%5B%5D%7B3%7D%20%5Cend%7Bgathered%7D)
Then, the solutions to the equation are:
x = 0
x = 3 - √3
x = 3 + √3
