Answer:
a) f=0.1 Hz ; b) T=10s
c)λ= 36m
d)v=3.6m/s
e)amplitude, cannot be determined
Explanation:
Complete question is:
Determine, if possible, the wave's (a) frequency, (b) period, (c) wavelength, (d) speed, and (e) amplitude.
Given:
number of wave crests 'n'= 5
pass in a time't' 54.0s
distance between two successive crests 'd'= 36m
a) Frequency of the waves 'f' can be determined by dividing number of wave crests with time, so we have
f=n/t
f= 5/ 54 => 0.1Hz
b)The time period of wave 'T' is the reciprocal of the frequency
therefore,
T=1/f
T=1/0.1
T=10 sec.
c)wavelength'λ' is the distance between two successive crests i.e 36m
Therefore, λ= 36m
d) speed of the wave 'v' can be determined by the product of frequency and wavelength
v= fλ => 0.1 x 36
v=3.6m/s
e) For amplitude, no data is given in this question. So, it cannot be determined.
This experiment help us understand their behavior as well as how the people will cop up with the rules and regulation the society wants to apply on them
<h3>What is Stanford prison experiment ?</h3>
In a two-week simulation of a prison setting, the Stanford prison experiment was meant to look at the impact of situational factors on participants' responses and behaviors.
Hence, this experiment allows us to better understand their behavior, as well as how individuals will respond to the laws and regulations imposed by society.
To learn more about the Stanford prison experiment, refer;
brainly.com/question/5014785
#SPJ1
The spring constant of the given spring is 250 N/m. Spring constant is the measure of the stiffness of the spring.
<h3>
What is the spring constant?</h3>
It is the measure of the stiffness of the spring or in other work how much a spring resists the deformation.
From Hooke's law,
- force - 75 N
- spring constant
- displacement - 0.3 m
Put the values in the formula and calculate for ,
Therefore, the spring constant of the given spring is 250 N/m.
Learn more about spring constant:
brainly.com/question/4291098
As we know that kinetic energy is given as
Here we can find the initial speed of puck A by momentum conservation
now here we will have initial kinetic energy of the mass is given as
now loss of energy is given as