No answer is possible, because you denied us the opportunity
to use any of the information in the picture.
Answer: Because the hunter will try to aim at the fish, but the image of fish he sees is actually the apparent image of the fish at a location.
Heres an image to help
Hope this helps!
<span>
A vacuum doesn't contain a medium.
Light, which is an electromagnetic
wave and doesn't require a medium,
will travel there. Sound, which is a
mechanical wave and requires a
medium, will not travel there.</span>
(You can see the light of the sun and other stars, which travels to us through
space. Astronauts can't hear the sound of each others' voices when they're
standing together on the moon because there's no medium between them,
so they have to use radio even to go only a few feet.)
Given what we know, as with all substances, the particles in the bowl of hot soup will slow down as they cool after being poured.
<h3>Why do particles slow when cooled?</h3>
- This has to do with energy.
- The soup particles are excited by heat energy.
- As the soup is poured, its heat energy radiates and it loses energy.
- Decreased energy causes the particles to slow down.
Therefore, the motion of the particles of the soup decrease or slows down as the soup cools due to the loss of energy they are experiencing. The soup radiates heat energy into the room or plate, causing the particles to lose energy and slow down.
To learn more about heat energy visit:
brainly.com/question/1495272?referrer=searchResults
Answer:
0.82 mm
Explanation:
The formula for calculation an 
bright fringe from the central maxima is given as:
so for the distance of the second-order fringe when wavelength 
= 745-nm can be calculated as:
where;
n = 2
= 745-nm
D = 1.0 m
d = 0.54 mm
substituting the parameters in the above equation; we have:
= 0.00276 m
= 2.76 × 10 ⁻³ m
The distance of the second order fringe when the wavelength 
= 660-nm is as follows:
= 1.94 × 10 ⁻³ m
So, the distance apart the two fringe can now be calculated as:
= 2.76 × 10 ⁻³ m - 1.94 × 10 ⁻³ m
= 10 ⁻³ (2.76 - 1.94)
= 10 ⁻³ (0.82)
= 0.82 × 10 ⁻³ m
= 0.82 × 10 ⁻³ m 
= 0.82 mm
Thus, the distance apart the second-order fringes for these two wavelengths = 0.82 mm
