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Doss [256]
3 years ago
13

Thinking about the impacts of socioeconomic status, you should A. consider the outside factors that are impacting that child's a

bility to learn and offer resources to the family when possible. B. talk with the family about their situation. C. use a standardized tool that's normed on children from low-income families. D. assume the child who may live in poverty won't perform as well as others from wealthier families.
Physics
2 answers:
diamong [38]3 years ago
7 0

The correct option is  A. consider the outside factors that are impacting that child's ability to learn and offer resources to the family when possible.

Took the pf test and got 100%

olchik [2.2K]3 years ago
6 0
I believe its a.consider the outside factors that are impacting that child's ability to learn and offer resources to the family when possible.because it is the most relevant one out of the choice  
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During its lifespan, what characteristics of the sun will change
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During its lifepsan, the sun's core would keep contracting and heating up.

The temperature will keep increasing to the point where the temperature outside the core will get to hydrogen fusion temperatures.
The sun will grow in surface and eventually became the Red Giant
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A car is traveling on the highway at 28 m/s The driver sees a tree in the middle of the road and slams on the brakes. The car co
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What is the slope of the line?
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(30, 5)
(10, 1)

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3 years ago
Which represents the net force
ipn [44]

Answer:

The net force is 500N downwards

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When Haley is trying to pull an object upward. The below forces are acting on the object.  

Fp = 5500N

Fg = 6000N

because the force of gravity is more than the force of the pull.

Fnet = Fg - Fp = 6000N - 5500N = 500N

And, the direction of the resultant force is the direction of the larger force.

4 0
3 years ago
The flywheel is rotating with an angular velocity ω0 = 2.37 rad/s at time t = 0 when a torque is applied to increase its angular
nika2105 [10]

Answer:

ω = 12.023 rad/s

α = 222.61 rad/s²

Explanation:

We are given;

ω0 = 2.37 rad/s, t = 0 sec

ω =?, t = 0.22 sec

α =?

θ = 57°

From formulas,

Tangential acceleration; a_t = rα

Normal acceleration; a_n = rω²

tan θ = a_t/a_n

Thus; tan θ = rα/rω² = α/ω²

tan θ = α/ω²

α = ω²tan θ

Now, α = dω/dt

So; dω/dt = ω²tan θ

Rearranging, we have;

dω/ω² = dt × tan θ

Integrating both sides, we have;

(ω, ω0)∫dω/ω² = (t, 0)∫dt × tan θ

This gives;

-1[(1/ω_o) - (1/ω)] = t(tan θ)

Thus;

ω = ω_o/(1 - (ω_o × t × tan θ))

While;

α = dω/dt = ((ω_o)²×tan θ)/(1 - (ω_o × t × tan θ))²

Thus, plugging in the relevant values;

ω = 2.37/(1 - (2.37 × 0.22 × tan 57))

ω = 12.023 rad/s

Also;

α = (2.37² × tan 57)/(1 - (2.37 × 0.22 × tan 57))²

α = 8.64926751525/0.03885408979 = 222.61 rad/s²

6 0
3 years ago
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