If 2.0j of work is done in raising 180g apple, how far was it lifted?
1 answer:
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Answer:
distance travelled by the block is 0.796 m
{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }
Explanation:
Given that;
mass of block m = 0.200 kg
distance travelled d = 0.796 m
time t = 2.00 s
m₂ = 0.400 kg
If the 0.400 kg block is released from rest at the top of the incline, how far down the incline does it travel in 2.00 s?
Now, using the second equation of motion;
d = ut + ( × at²)
as the object started from rest, u=0
so, we substitute
0.796 = 0×2 + ( × a(2)²)
0.796 = 0 + ( × 4a)
0.796 = 2a
a = 0.796 / 2
a = 0.398 m/s²
using first equation of motion
= u + at
we substitute
= 0 + 0.398 × 2
= 0.796 m/s
now, average velocity is given as;
= ( 0.796 m/s + 0 ) / 2
= ( 0.796 m/s + 0 ) / 2
now, distance as the block moves in 2s will be;
D = [( 0.796 m/s + 0 ) / 2 ] × 2
D = 0.796 m
Therefore, distance travelled by the block is 0.796 m
{ acceleration is independent of mass, so both the masses travel equal distance in 2 s }