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2 years ago

How is the atomic mass of an element related to a mole?

Chemistry

1 answer:

Luden [163]2 years ago

4 0

Answer:

i the answer to your question should be C

Explanation:

Hope this helps!

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A rocket accelerates at 56 m/s2 with the force of 44,800 N. What is the mass of the rocket?

nekit [7.7K]

Answer:

800 kg 5

Explanation:

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3 years ago

A chunk of copper has a volume of 1.45 mL and a mass of 12.93 grams. What is the density of the chunk of copper?

natta225 [31]

Answer:

$Density = 8.92 \ g/mL$

Explanation:

The equation for density is:

$Density = \frac{mass}{volume}$

We plug in the given values:

$Density = \frac{12.93 \ g}{1.45 \ mL}$

$Density = 8.92 \ g/mL$

7 0

3 years ago

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What numbers are shown in the symbol for a radioactive nuclide

Bingel [31]

The atomic # and the mass #.

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3 years ago

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Enter the atomic symbol, including mass number and atomic number, for iodine-130.

WINSTONCH [101]

Answer: The atomic symbol of the given element is $_{53}^{130}\textrm{I}$

Explanation:

The general isotopic representation of an element is given as: $_Z^A\textrm{X}$

where,

Z represents the atomic number of the element

A represents the mass number of the element

X represents the symbol of an element

For the given isotope: 130-iodine

Mass number = 130

Atomic number = 53

Hence, the atomic symbol of the given element is $_{53}^{130}\textrm{I}$

6 0

3 years ago

The acid HOCl (hypochlorous acid) is produced by bubbling chlorine gas through a suspension of solid mercury(II) oxide particles

sergejj [24]

Answer: The expression for equilibrium constant is $K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

For the general chemical equation:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_c$ is given as:

$K_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

For the given chemical reaction:

$2HgO(s)+H_2O(l)+2Cl_2(g)\rightleftharpoons 2HOCl(aq.)+HgO.HgCl_2(s)$

The expression for $K_{eq}$ is given as:

$K_{eq}=\frac{[HOCl]^2[HgO.HgCl_2]}{[HgO]^2[H_2O][Cl_2]^2}$

The concentration of solid is taken to be 0.

So, the expression for $K_{eq}$ is given as:

$K_{eq}=\frac{[HOCl]^2}{[H_2O][Cl_2]^2}$

3 0

4 years ago