Name some of the chemical substances in a tea mixture

1 Srcl (aq) + 1 H,60,(aq) → 2 HCl(aq) + 1 Srso (s)

Mrac [35]

Answer:

Mass = 245.72 g

Explanation:

Given data:

Mass of SrCl₂ react = ?

Mass of H₂SO₄ = 300.0 g

Solution:

SrCl₂ + 2H₂SO₄ → 2HCl + Sr(HSO₄)₂

Number of moles of H₂SO₄:

Number of moles = mass/molar mass

Number of moles = 300.0 g/ 98.079 g/mol

Number of moles = 3.1 mol

Now we will compare the moles of SrCl₂ and H₂SO₄.

H₂SO₄ : SrCl₂

2 : 1

3.1 : 1/2×3.1 = 1.55 mol

Mass of SrCl₂:

Mass = number of moles × molar mass

Mass = 1.55 mol × 158.53 g/mol

Mass = 245.72 g

3 0

3 years ago

What is the density of platinum

Alex Ar [27]

Answer:

21.45 g/cm3

Explanation:

6 0

3 years ago

Read 2 more answers

In the artice, "As Sticky as a Gecko...but Ten

ra1l [238]

Answer:

The adhesive is made up of two different layers.

The lower layer is made up of vertically aligned nanotubes.

The upper layer is made up of curly, spaghetti-like, nanotubes.

6 0

2 years ago

Read 2 more answers

I went to the doctor for a check-up last week. First, she examined the (1) ___ portion of my body by listening to my heart and t

Zinaida [17]

1. medial
2.superior
3. inferior
4.lateral
5.inferior

7 0

3 years ago

Calcium carbonate is often used as an antacid. Your stomach acid is composed of HCl at a pH of 1.5. If you ate toooo much Turkey

stiks02 [169]

<u>Answer:</u> 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

<u>Explanation:</u>

pH is defined as the negative logarithm of hydrogen ion concentration present in the solution

$pH=-\log [H^+]$ .....(1)

Given value of pH = 1.5

Putting values in equation 1:

$1.5=-\log[H^+]$

$[H^+]=10^{(-1.5)}=0.0316M$

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

$\text{Molarity of solution}=\frac{\text{Number of moles of solute}\times 1000}{\text{Volume of solution (mL)}}$ .....(2)

We are given:

Volume of solution = 15.0 mL

Molarity of HCl = 0.0316 M

Putting values in equation 2:

$0.0316=\frac{\text{Moles of HCl}\times 1000}{15.0}\\\\\text{Moles of HCl}=\frac{0.0316\times 15.0}{1000}=4.74\times 10^{-4}mol$

The chemical equation for the reaction of HCl and calcium carbonate follows:

$2HCl+CaCO_3\rightarrow H_2CO_3+CaCl_2$

By the stoichiometry of the reaction:

2 moles of HCl reacts with 1 mole of calcium carbonate

So, $4.74\times 10^{-4}mol$ of HCl will react with = $\frac{1}{2}\times 4.74\times 10^{-4}=2.37\times 10^{-4}mol$ of calcium carbonate

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Moles of calcium carbonate = $2.37\times 10^{-4}mol$

Molar mass of calcium carbonate = 100.01 g/mol

Putting values in the above equation:

$\text{Mass of }CaCO_3=(2.37\times 10^{-4}mol)\times 100.01g/mol\\\\\text{Mass of }CaCO_3=0.0237g$

Hence, 0.0237 g of calcium carbonate would be required to neutralize the given amount of HCl

7 0

2 years ago