Answer:
They are in a periodic table
The kind of chemical catalysis is covalent catalysis and among the given amino acids lysine will act as a catalyst for the reaction.
The generation of iminium ions in the transition state of the reaction confirms that it is a covalent catalysis. lysine is the only amino acid that can catalyze the iminium ion generated in the transition state of the reaction.
So the answer for the type of catalysis is covalent catalysis, and the answer for the type of amino acid among the given amino acids that can catalyze the reaction is lysine.
Complete question: (Reaction is attached as a picture)
You can also learn about chemical catalysis from the following question:
brainly.com/question/13553173
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It contains 23000/13= 1769.23 C¹³ atoms
Answer:- pH is 2.14.
Solution:- Nitrous acid,
is a weak acid so first of all we solve for
and then figure out the pH.
the equation is written as:

Initial concentration for the acid is given as 0.120 M. Let's say the change in concentration is x. Then the equilibrium concentrations would be as:

= 
= 
Ka for nitrous acid is
and the equilibrium expression for this would be written as:
![Ka=\frac{[H_3O^+][NO_2^-]}{HNO_2}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BNO_2%5E-%5D%7D%7BHNO_2%7D)
Let's plug in the values in it.

To make the calculations easy we could ignore
for the bottom and the expression becomes:

On cross multiply:

On taking square root to both sides:

So, ![[H_3O^+]=7.3*10^-^3M](https://tex.z-dn.net/?f=%5BH_3O%5E%2B%5D%3D7.3%2A10%5E-%5E3M)
Now we could calculate the pH using the pH formula:
![pH=-log[H_3O^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH_3O%5E%2B%5D)

pH = 2.14
So, the pH of 0.120M nitrous acid is 2.14.