Show the alkyl bromide and alcohol used to make methyl t-butyl ether using the Williamson ether synthesis to the right of the re

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Show the alkyl bromide and alcohol used to make methyl t-butyl ether using the Williamson ether synthesis to the right of the re

trosynthetic arrow. alcohol alkyl bromide click to edit CHa H3 H3 b) Complete the general mechanism by adding curved arrows and drawing the final organic product. (Note that R is an abbreviation for any alkyl group and can be found on the bottom row in the pull down periodic table in the drawing tools menu.) product Na +RX

Chemistry

1 answer:

Korolek [52] · Answer 1 · 2022-06-23T10:26:08+03:00

Answer:

Hi

Williamson's ether reactions imply that an alkoxide reacts with a primary haloalkane. Alkoxides consisting of the conjugate base of an alcohol and are formed by a group R attached to an oxygen atom. They are often written as RO–, where R is the organic substituent (Step 1).

Sn2 reactions are characterized by the reversal of stereochemistry at the site of the leaving group. Williamson's synthesis is no exception and the reaction is initiated by the subsequent attack of the nucleophile. This requires that the nucleophile and electrophile be in anti-configuration (Step 2).

As an example (figure 3).

In the attached file are each of the steps of Williamson's synthesis.

Explanation:

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