1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MaRussiya [10]
3 years ago
13

Please help me with some extra details please

Chemistry
1 answer:
mojhsa [17]3 years ago
6 0

Answer:

Empirical Formula: Al_2O_3

Explanation:

Since total mass is 306, we have:

Mass of $Al = \frac{52.9}{100}\times 306=161.87 $

Mass of $O= \frac{47.1}{100}\times 306=144.126$

Hence,

Moles of $Al=\frac{Mass}{molar mass}=\frac{161.87}{27}=6$

Moles of $O= \frac{Mass}{molar mass}=\frac{144.126}{16}=9$

Hence the formula is $Al_6O_9$ , or, $Al_2O_3$

You might be interested in
When 5.00 g of Al2S3 and 2.50 g of H2O are reacted according to the following reaction: Al2S3(s) + 6 H2O(l) → 2 Al(OH)3(s) + 3 H
Debora [2.8K]

Answer:

Y=58.15\%

Explanation:

Hello,

For the given chemical reaction:

Al_2S_3(s) + 6 H_2O(l) \rightarrow 2 Al(OH)_3(s) + 3 H_2S(g)

We first must identify the limiting reactant by computing the reacting moles of Al2S3:

n_{Al_2S_3}=5.00gAl_2S_3*\frac{1molAl_2S_3}{150.158 gAl_2S_3} =0.0333molAl_2S_3

Next, we compute the moles of Al2S3 that are consumed by 2.50 of H2O via the 1:6 mole ratio between them:

n_{Al_2S_3}^{consumed}=2.50gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molAl_2S_3}{6molH_2O}=0.0231mol  Al_2S_3

Thus, we notice that there are more available Al2S3 than consumed, for that reason it is in excess and water is the limiting, therefore, we can compute the theoretical yield of Al(OH)3 via the 2:1 molar ratio between it and Al2S3 with the limiting amount:

m_{Al(OH)_3}=0.0231molAl_2S_3*\frac{2molAl(OH)_3}{1molAl_2S_3}*\frac{78gAl(OH)_3}{1molAl(OH)_3} =3.61gAl(OH)_3

Finally, we compute the percent yield with the obtained 2.10 g:

Y=\frac{2.10g}{3.61g} *100\%\\\\Y=58.15\%

Best regards.

7 0
3 years ago
Joshua hooks a rubber band between his thumb and forefinger. He moves his fingers apart, stretching the rubber band. With a quic
Gnoma [55]
<span>The elastic potential energy stored in the stretched rubber band changes to kinetic energy.</span>
5 0
3 years ago
Read 2 more answers
A student investigates the properties of an unknown liquid substance in a beaker. The student finds the substance has a mass of
shtirl [24]

Answer:

The substance is a mixture because it left a white powder in the beaker when boiled.

Explanation:

8 0
3 years ago
Matthew has been collecting quarters in a jar. He has 176 quarters. What is the value of the coins in his jar?
AURORKA [14]

Answer:

The correct answer is : 44 dollars.

Explanation:

A quarter is one fourth of a dollar that is the reason it is known as quarter. A quarter is 25 cents or 0.25 dollar in value. If Matthew has 176 quarters in his jar than the value of the total coins would be:

1 quarter = 0.25 dollar

1 quarter = 1/4 dollar.

4 quarter = 1 dollar

then, 176 / 4 = x dollar

 = 44 dollar

Thus, The correct answer is : 44 dollars.

3 0
3 years ago
To find S, the number of shared
Anton [14]

Answer:

It’s 6 :)

Explanation:

3 0
3 years ago
Other questions:
  • The number of nucleons in an atom is the atom's (atomic, mass) number.
    13·2 answers
  • Jeremy hypothesized that adults with blue eyes are shorter than adults with brown eyes. He collected data by visiting all of the
    15·2 answers
  • How are continental drift and plate tectonics related
    9·1 answer
  • I need help!!!! Plz help me with the above question
    15·1 answer
  • A sample of an ideal gas has a volume of 2.21 L at 282 K and 1.03 atm. Calculate the pressure when the volume is 1.84 L
    11·1 answer
  • What is the approximate percent by mass of potassium in KHCO3?
    11·1 answer
  • (25points) Explain in your own words the difference between atomic mass and atomic number. Where can you find this information o
    9·2 answers
  • Which of the following increases the concentration of OH- ions?
    8·2 answers
  • Given that a 3cm lenght of magnesium weights approximately 0.04g, calculate the number of moles of acid that reacted with the 9c
    11·1 answer
  • X(OH)2 + 2HCl XCl2 +2H2O
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!