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Lena [83]
3 years ago
10

f(x)= 1 / x-3 g(x)= 3x + 1/x A. Use composition to prove whether or not the functions are inverses of each other. B. Express the

domain of the compositions using interval notation. Please answer this worth 20 points
Mathematics
1 answer:
Alisiya [41]3 years ago
7 0

Step-by-step explanation:

(A) To find inverse of f(x) = y = 1 / x - 3 :

<u>Transform in terms of x</u>

y = 1 / x - 3

x - 3 = 1 / y

x = 3 + 1 / y

<u>Exchange x with y</u> :

{f}^{ - 1} (x) = 3 +  \frac{1}{x}

Therefore, g(x) is not inverse of f(x) and vice versa.

(B)

Domain of f(x) = R - {3}

Domain of g(x) = R - {0}

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2 years ago
Find the value of k so that 48x-ky=11 and (k+2)x+16y=-19 are perpendicular lines.
Rufina [12.5K]

Answer: k = -1 +/- √769

<u>Step-by-step explanation:</u>

48x - ky = 11

<u>-48x        </u>  <u> -48x</u>

         -ky = -48x + 11

         \frac{-ky}{-k} = \frac{-48x}{-k} + \frac{11}{-k}    

           y =\frac{48x}{k} - \frac{11}{k}

Slope: \frac{48}{k}

*************************************************************************

 (k + 2)x + 16y = -19

<u>- (k + 2)x          </u>   -<u>(k + 2)x </u>

                 16y = -(k + 2)x - 19

                  \frac{16y}{16} = -\frac{(k + 2)x}{16} - \frac{19}{16}

                  y = -\frac{(k + 2)x}{16} - \frac{19}{16}

Slope: -\frac{(k + 2)}{16}

**********************************************************************************

\frac{48}{k} and -\frac{(k + 2)}{16} are perpendicular so they have opposite signs and are reciprocals of each other.  When multiplied by its reciprocal, their product equals -1.

-\frac{(k + 2)}{16} *  \frac{k}{48} = -1

\frac{(k + 2)k}{16(48)} = 1

Cross multiply, then solve for the variable.

(k + 2)(k) = 16(48)

k² + 2k - 768 = 0

Use quadratic formula to solve:

k = -1 +/- √769



5 0
3 years ago
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