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3 years ago

How to get more water pressure in shower?

1 answer:

4 0

I picked up cost $1.50). If you look down inside of the showerhead you'll see a washer which constricts the water flow. If you take a drill and enlarge the hole, thereby increasing flow, the water pressure will increase

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The basic building blocks of matter is the -----

stiks02 [169]

The basic building blocks of matter is the atom.

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4 years ago

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"If E = 7.50V and r=0.45Ω, find the minimum value of the voltmeter resistance RV for which the voltmeter reading is within 1.0%

Virty [35]

Answer:

The minimum value is $R_V =44.552\ \Omega$

Explanation:

From the question we are given that

The voltage is $E = 7.5V$

The internal resistance is $r = 0.45$

The objective of this solution is to obtain the minimum value of the voltmeter resistance for which the voltmeter reading is within 1.0% of the emf of the battery

What is means is that we need to obtain voltmeter resistance such that

V = (100% -1%) of E

Where E is the e.m.f of the battery and V is the voltmeter reading

i.e V = 99% of E = 0.99 E = 7.425

Generally

E = V + ir

where ir is the internal potential difference of the voltmeter and

V is the voltmeter reading

Making i the subject of the formula above

$i = \frac{(E-V)}{r}$

$=\frac{7.50-7.425}{0.45}$

$= 0.1667 A$

Now the current is constant through out the circuit so,

$V = iR_V$

Where $R_V$ is the value of voltmeter resistance

Hence $R_V = \frac{V}{i} = \frac{7.425}{0.1667}$

$=44.552\ \Omega$

8 0

4 years ago

Which of the following amounts to a scientific research process that can be replicated?

STALIN [3.7K]

Answer:

D.all of the above

Explanation:

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2 years ago

Light of wavelength 630 nm is incident on a long, narrow slit. Determine the angular deflection of the first diffraction minimum

asambeis [7]

Answer:

a) 1.8°

b) 0.18°

c) 0.018°

Explanation:

Wavelength (λ) = 630nm = 630 *10^-9m

The equation that describes the angular deflection of a dark band is

Wsin(βm) = mλ

w = width of the single slit

λ = wavelength of the light

βm = angular deflection of the mth dark band.

a) In order to get the angular deflection of the first dark band for a slit with 0.02mm width, substitute w = 0.02mm = 0.02*10^-3 , m = 1 , λ= 630*10^-9

0.02*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 0.02*10^-3

Sin(β1) = 0.0315

β1 = Sin^-1(0.0315)

= 1.8°

b) substitute w = 0.2mm = 0.2*10^-3 , m = 1 , λ= 630*10^-9

0.2*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 0.2*10^-3

Sin(β1) = 0.00315

β1 = Sin^-1(0.00315)

= 0.18°

c) substitute w = 2mm = 2*10^-3 , m = 1 , λ= 630*10^-9

2*10^-3 sin(β1) = 1 * 630*10^-9

Sin(β1) = 630 * 10^-9 / 2*10^-3

Sin(β1) = 3.15*10^-4

β1 = Sin^-1(3.15*10^-4)

= 0.018°

6 0

3 years ago

How many meters in 32 kilometers

Alisiya [41]

Hello !

32 km = 32000 m

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3 years ago

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