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vitfil [10]
4 years ago
11

The following diagram represents a cart with an initial velocity of 1.0 m/s sliding along a frictionless track from point A

Physics
1 answer:
ki77a [65]4 years ago
7 0

Answer:

point b

Explanation:

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Does the materialist position imply a determinist position on the possibility of free will? explain.
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<span>Materialism claims that reality consist of physical objects and their components. 
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3 years ago
A 15 kg runaway grocery cart runs into a spring with spring constant 230 N/m and compresses it by 56 cm .What was the speed of t
liubo4ka [24]

To solve this problem we will apply the concepts related to the conservation of kinetic energy and elastic potential energy. Thus we will have that the kinetic energy is

KE = \frac{1}{2} mv^2

And the potential energy is

PE = \frac{1}{2} kx^2

Here,

m = mass

v = Velocity

x = Displacement

k = Spring constant

There is equilibrium, then,

KE = PE

\frac{1}{2} mv^2 = \frac{1}{2} kx^2

Our values are given as,

x=0.56m\\k=230N/m\\m=15kg

Replacing we have that

\frac{1}{2} (15)v^2 = \frac{1}{2} (230)(0.56)^2

v = 2.19m/s

Therefore the speed of the cart is 2.19m/s

3 0
4 years ago
5 renewable energy resources<br> i have nuclear, solar, wind<br> what am i missin?
Tamiku [17]

Answer:

Solar energy.

Wind energy.

Hydro energy.

Tidal energy.

Geothermal energy.

Biomass energy.

6 0
3 years ago
Which of newtons laws accounts for the following statement " Negative acceleration is proportional to applied braking force "
fenix001 [56]
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4 years ago
Welcome to this IE. You may navigate to any page you've seen already using the IE Outline tab on the right. A particle beam is m
Genrish500 [490]

Answer:

the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

Explanation:

Given the data in the question;

Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J

Mass of proton = 1.673 × 10⁻²⁷ kg

Charge of proton = 1.602 × 10⁻¹⁹ C

distance d = 2 m

we know that

Kinetic Energy = Charge of proton × Potential difference ΔV

so

Potential difference ΔV = Kinetic Energy / Charge of proton

we substitute

Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )

Potential difference ΔV = 20287.14 V

Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;

E = Potential difference ΔV / distance d

we substitute

E = 20287.14 V / 2 m

E = 10143.57 V/m or 1.01 × 10⁴ V/m

Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m

3 0
3 years ago
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