Answer:
300.16m/s
Explanation:
An artillery shell is fired at an angle to the horizontal. Its initial velocity has a vertical component of 150 meters per second and a horizontal component of 260 meters per second. What is the magnitude of the initial velocity of the shell?
note velocity is the change in displacement to time
to find the magnitude of the initial speed ,
we will find the square of the vertical component plus the square of the horizontal component. then we look for the square root
U=
U=
U=90,100^2
U=300.16m/s
means that it covers 300.16m in 1 seconds
Answer:
a ) 
b) 
Explanation:
given data:
pressure ration rp = 12
inlet temperature = 300 K
TURBINE inlet temperature = 1000 K
AT the end of isentropic process (compression) temperature is
AT the end of isentropic process (expansion) temperature is
isentropic work is given as
w = 1.005(610.18 - 300)
w = 311.73 kJ/kg
w(turbine) = 1.005( 1000 - 491.66)
w(turbine) = 510.88 kJ/kg
a) mass flow rate for isentropic process is given as
b) actual mass flow rate uis given as
Answer:
Power in the circuit is 0.1 amp
Explanation:
The power in the circuit is given by the formula
P = V x I
Where P is Power, V is voltage supplied and I is current in circuit.
so, I = P/v
= 2/20
=0.1 A
Study more about power
<u>https://brainly.in/question/1063947</u>
Answer:
Shiloh dynasty, jucie wrld or xxx or twenty one plot
Explanatio
Vf = 0 + 3.5•8.7
= 30.45 m/s
