1. its must be B and 2. must be C
The gravitational potential energy will increase by 423.36 J
<h3>How to determine the potential energy at ground level</h3>
- Mass (m) = 72 kg
- Acceleration due to gravity (g) = 9.8 m/s²
- Height (h) = 0 m
- Potential energy at ground level (PE₁) =?
PE = mgh
PE₁ = 72 × 9.8 × 0
PE₁ = 0 J
<h3>How to determine the potential energy at 60 cm (0.6 m)</h3>
- Mass (m) = 72 kg
- Acceleration due to gravity (g) = 9.8 m/s²
- Height (h) = 0.6 m
- Potential energy at 60 cm (0.6 m) (PE₂) =?
PE = mgh
PE₂ = 72 × 9.8 × 0.6
PE₂= 423.36 J
<h3>How to determine the change in potential energy </h3>
- Potential energy at ground level (PE₁) = 0 J
- Potential energy at 60 cm (0.6 m) (PE₂) = 423.36 J
- Change in potential energy =?
Change in potential energy = PE₂ - PE₁
Change in potential energy = 423.36 - 0
Change in potential energy = 423.36 J
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Answer:
108.217 °
Explanation:
Day of year = 356 = d (Considering year of 365 days)
Latitude of Tropic of Cancer = 23.5 °N
Declination angle
δ = 23.45×sin[(360/365)(d+284)]
⇒δ = 23.45×sin[(360/365)(356+284)]
⇒δ = 5.2832 °
Altitude angle at solar noon
90+Latitude-Declination angle
= 90+23.5-5.2832
= 108.217 °
∴ Altitude angle of the Sun as seen from the tropic of cancer on December 22 is 108.217 °
Answer:
F = 3.6 x 10⁻²⁴ N
Explanation:
The force of attraction or repulsion between two charges is given by the Coulomb's Law. Coulomb's Law states that:
F = kq₁q₂/r²
where,
F = Electric Force between electrons = ?
k = Coulomb's Constant = 9 x 10⁹ N.m²/C²
q₁ = q₂ = Charge on electron = 1.6 x 10⁻¹⁹ C
r = distance between electrons = 0.8 cm = 0.008 m
Therefore,
F = (9 x 10⁹ N.m²/C²)(1.6 x 10⁻¹⁹ C)(1.6 x 10⁻¹⁹ C)/(0.008 m)²
<u>F = 3.6 x 10⁻²⁴ N</u>
