True
False
True
My answers
"60 kg" is not a weight. It's a mass, and it's always the same
no matter where the object goes.
The weight of the object is
(mass) x (gravity in the place where the object is) .
On the surface of the Earth,
Weight = (60 kg) x (9.8 m/s²)
= 588 Newtons.
Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to 5R from the center, the gravity out there is
(1R/5R)² = (1/5)² = 1/25 = 0.04 of its value on the surface.
The object's weight would also be 0.04 of its weight on the surface.
(0.04) x (588 Newtons) = 23.52 Newtons.
Again, the object's mass is still 60 kg out there.
___________________________________________
If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
60 kilograms, then you should be raising a holy stink.
You are being planted with sloppy, inaccurate, misleading
information, and it's going to be YOUR problem to UN-learn it later.
They owe you better material.
Answer:
Explanation:
In series combination, the equivalent resistance is given by :
Let the identical resistors be R. We have, 
So,
So, the resistance of each resistor is 
.
Answer:
Taking gravity to be 9.8m/s2, The velocity is 24.5m/s2.
Taking gravity to be 10m/s2, The velocity is 25m/s2.
Explanation:
According the first formula of motion under the influence of gravity for upward motion, v=u-gt, where v=final velocity, u=initial velocity, and t= time taken.
Here the time taken for the ball to reach the maximum point is half of 5, which is 2.5 seconds.
And v is 0, since at the maximum point gravity slows down the velocity to 0.
Finding the initial velocity,
v=u-gt
0=u-10(2.5)
u=10(2.5)
u=25m/s
