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3 years ago

Conventionally, the field strength around a charged object is the direction of the force acting on a .

Physics

2 answers:

damaskus [11]3 years ago

8 0

Answer:

Field Strength:

Any charged body has the capacity to effect any test charge that comes inside its field or region. It can be also defined as,

"The total amount or magnitude of force,F or intensity felt by any unit test charge when it enters an electromagnetic or electric field."

For an electric field its unit will be, volt per meter or simply V/m.

Explanation:

A unit test charge inside an electric field:

When a unit test charge enters a given parameters or area set by the charged particle then it will surely experience a force,F equal to the magnitude of that charge body and it will be different as it continues to move closer or far inside the field.

As, we have, "E=F/q",(where "F" is the field strength and "q" is the unit test charge placed inside the field).

ExtremeBDS [4]3 years ago

7 0

Unit positive test charge

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Answer:

3/4

Explanation:

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3 years ago

The body weighing 2 kg moves through the horizontal surface and crosses the path x = 75 cm The coefficient of friction of the bo

Taya2010 [7]

The kinetic energy of the body in definitive position is 4.24 J.

Explanation:

As per the work energy theorem, the work done on any system or object to move it from one position to another is equal to the change in kinetic energy of the object. In this case, the body weighing 2 kg is moved over an horizontal surface for a distance of 75 cm. As there will be frictional force acting on the body while moving over the surface. This frictional force multiplied by the distance the object is moved will give the work done on the body.

Frictional force = Coeffficent of friction × Normal force.

As the weight of the body is 2 kg, the normal force acting on it will be mass multiplied with acceleration due to gravity.

Frictional force = - 0.8×9.8 × 2 =-15.68 N

So the work done will be the product of frictional force with the displacement of 75 cm or 0.75 m.

Work done = Frictional force × Displacement

Work done = -15.68×0.75 = -11.76 J.

So the work is done by the object.

If the kinetic energy of the body at starting is 16 J, then the kinetic energy of the body at definitive position will be obtained as below.

Work done = change in kinetic energy

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3 years ago

What is the answer to this question number 2?

anzhelika [568]

Answer:

1⁺ ion

Explanation:

Metals in the first group on the periodic table will prefer to form 1⁺ ion. This is because the 1 valence electron in their orbital.

Most metals are electropositive and would prefer to lose electrons than to gain it.

Like all metals, the group 1 elements called the alkali metals would prefer to lose and electron.

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3 years ago

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konstantin123 [22]

"Frequency" just means "often-ness" ... how often something happens.
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3 years ago

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r-ruslan [8.4K]

I'm pretty sure the energy an object acquires when exposed to a force is known was potential energy.

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