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DochEvi [55]
2 years ago
14

What value(s) of x will make x2 = 25 true? A. 5 and -5 B. 5 C. 5 D. 12.5 and -12.5

Mathematics
1 answer:
Dima020 [189]2 years ago
3 0

x^2 = 25

x = -5, 5

Check your work!

(-5)^2 = 25

(5)^2 = 25

Hope this helps! :)

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Step-by-step explanation:

12:36=\dfrac{12}{36}=\dfrac{12:12}{36:12}=\dfrac{1}{3}

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42 + 6 divided by 2 equals 24
3 0
3 years ago
10. What is the distance between (8,7) and (3,-5)?
Anarel [89]

Answer:

distance between points=13 units

Step-by-step explanation:

distance between points=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

put (x_1,x_2)=(8,7) and (y_1,y_2)=(3,-5)

distance between points=\sqrt{(3-8)^2+(-5-7)^2}

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distance between points=\sqrt{25+144}

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8 0
3 years ago
All students = 700
Sedaia [141]

Answer:

  • See below

Step-by-step explanation:

<u>Given:</u>

  • Total number = 700
  • Off grid class = 450
  • Online class = 320
  • Both = 275

<u>Based on the given we find the following</u>

1) <u>Off-grid class only:</u>

  • 450 - 275 = 175

3) <u>Online class only:</u>

  • 320 - 275 = 45

2) <u>None of the classes:</u>

  • 700 - (175 + 275 + 45) = 205

4) <u>Not online:</u>

  • 700 - 320 = 380

5) <u>Not off-grid:</u>

  • 700 - 450 = 250
7 0
2 years ago
Annual starting salaries for college graduates with degrees in business administration are generally expected to be between $10,
Andreyy89

Answer:

1) the planning value for the population standard deviation is 10,000

2)

a) Margin of error E = 500, n = 1536.64 ≈ 1537

b) Margin of error E = 200, n = 9604

c) Margin of error E = 100, n = 38416

3)

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

Step-by-step explanation:

Given the data in the question;

1) Planning Value for the population standard deviation will be;

⇒ ( 50,000 - 10,000 ) / 4

= 40,000 / 4

σ = 10,000

Hence, the planning value for the population standard deviation is 10,000

2) how large a sample should be taken if the desired margin of error is;

we know that, n = [ (z_{\alpha /2 × σ ) / E ]²

given that confidence level = 95%, so z_{\alpha /2  = 1.96

Now,

a) Margin of error E = 500

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 500 ]²

n = [ 19600 / 500 ]²

n = 1536.64 ≈ 1537

b) Margin of error E = 200

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 200 ]²

n = [ 19600 / 200 ]²

n = 9604

c)  Margin of error E = 100

n = [ (z_{\alpha /2 × σ ) / E ]²

n = [ ( 1.96 × 10000 ) / 100 ]²

n = [ 19600 / 100 ]²

n = 38416

3) Would you recommend trying to obtain the $100 margin of error?

As we can see, sample size corresponding to margin of error of $100 is too large and may not be feasible.

Hence, I will not recommend trying to obtain the $100 margin of error in the present case.

7 0
2 years ago
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