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2 years ago

What is the chemical formula for Sodium bicarbonate

Chemistry

1 answer:

Cloud [144]2 years ago

5 0

Answer: Na2CO3

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4. Calculate the final concentration if water is added to 1.5 L of a 12 M

konstantin123 [22]

Answer:

Explanation:

(Molarity x Volume)concentrated soln = (Molarity x Volume)diluted doln

Molarity dilute soln = [(M x V)conc/V (dilute)] = 1.5L x 12M / 3.0L = 6M final dilute soln

6 0

3 years ago

In the laboratory, a general chemistry student measured the pH of a 0.529 M aqueous solution of phenol (a weak acid), C6H5OH to

Artyom0805 [142]

Answer:

The dissociation constant of phenol from given information is $9.34\times 10^{-11}$ .

Explanation:

The measured pH of the solution = 5.153

$C_6H_5OH\rightarrow C_6H_5O^-+H^+$

Initially c

At eq'm c-x x x

The expression of dissociation constant is given as:

$K_a=\frac{[C_6H_5O^-][H^+]}{[C_6H_5OOH]}$

Concentration of phenoxide ions and hydrogen ions are equal to x.

$pH=-\log[x]$

$5.153=-\log[x]$

$x=7.03\times 10^{-6} M$

$K_a=\frac{x\times x}{(c-x)}=\frac{x^2}{(c-x)}=\frac{(7.03\times 10^{-6} M)^2}{ 0.529 M-7.03\times 10^{-6} M}$

$K_a=9.34\times 10^{-11}$

The dissociation constant of phenol from given information is $9.34\times 10^{-11}$ .

4 0

3 years ago

What is shown in the diagram below?

Colt1911 [192]

B I think is right. Hope this helps!

3 0

2 years ago

Read 2 more answers

A solution contains 0.775 g Ca2 0.775 g Ca2 in enough water to make a 1925 mL1925 mL solution. What is the milliequivalents of C

Romashka [77]

Answer: There will be 0.00002 meq per Liter of the solution.

Explanation:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

$Normality=\frac{\text{no of gram equivalents} \times 1000}{\text{Volume in ml}}$

$Normality=\frac{\text{given mass}\times 1000}{\text {Equivalent mass}\times {\text{Volume in ml}}}$

Equivalent weight is calculated by dividing the molecular weight by n factor. ${\text{Equivalent weight}}=\frac{\text{Molecular weight}}{n}$

n= charge for charged species , For $Ca^{2+}$ , n =2

${\text{Equivalent weight}}=\frac{40}{2}=20g$

$\text{no of gram equivalents}=\frac{0.775g}{20g/mol}=0.04gramequivalents$

$Normality=\frac{0.04\times 1000}{1925}=0.02eq/L=0.00002meq/L$

Thus there will be 0.00002 meq per Liter of the solution.

3 0

3 years ago

It took 25 seconds for a horse to complete a 400 meter race. What was the speed of the horse?

Pani-rosa [81]

Answer:

v = 16 m/s

Explanation:

Given that,

Distance, d = 400 m

Time taken, t = 25 s

We need to find the speed of the horse. Speed is equal to distance covered divided by time taken. So,

$v=\dfrac{d}{t}\\\\v=\dfrac{400\ m}{25\ s}\\\\v=16\ m/s$

So, the speed of the horse is 16 m/s.

4 0

2 years ago