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Paha777 [63]
3 years ago
5

The diameters of apples from a certain farm follow the normal distribution with mean 4 inches and standard deviation 0.4 inch. A

pples can be size-sorted by being made to roll over mesh screens. First the apples are rolled over a screen with mesh size 3.5 inches. This separates out all the apples with diameters less than 3.5 inches. Second, the remaining apples are rolled over a screen with mesh size 4.3 inches. Find the proportion of apples with diameters less than 3.5 inches.
Physics
2 answers:
jeka943 years ago
8 0

Answer:

P = 10%

Explanation:

Let,

  • µ = mean of the population = 4 inches
  • σ = standard deviation = 0.4 inches
  • X= a random variable that gives apple’s diameter
  • P [X < 3.5] = P-value is the probability of apples which will be separated after passing through the mesh screen

After putting all the values in the formula, we will find the value of Z-score from the chart.

P [X < 3.5]      = P [ \frac{X-4}{0.4} < \frac{3.5-4}{0.4} ]

P [Z < -1.25]    = 0.09680

About 10% of the apples possess diameters less than 3.5 inches.

trasher [3.6K]3 years ago
7 0

Answer:

The probability for the proportion of apples with diameters less than 3.5 inches is 0.1056.

Explanation:

For a normal distribution, z score is calculated using this formula:  (X-μ)/σx

Where Mean, μ = 4

Standard deviation, σ = 0.400

The probability for the proportion of apples with diameters less than 3.5 inches is expressed below:

Probability = P(X<3.5)

                  = P(Z<-1.25)

Probability  = 0.1056

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PIT_PIT [208]

Answer:

E  = -6 \  N/C

Generally given that the electric field is negative it mean that its direction is opposite to that of the force    

Explanation:

From the question we are told that

   The charge on the small object is Q = -4.00 \ nC =  -4.00 *10^{-9} \  C

   The force is  F  =  24  \ nN  =  24 *10^{-9} \  N

    Generally the magnitude of the electric  field is mathematically represented as

       E  =  \frac{F}{Q}

=>    E  =  \frac{ 24 *10^{-9}} {-4 *10^{-9 }}

=>     E  = -6 \  N/C

Generally given that the electric field is negative it mean that its direction is opposite to that of the force    

 

6 0
3 years ago
There is less oxygen in air at higher altitudes than at sea level. Scientists have shown that people living at sea level have 5
Ivanshal [37]

Answer with Explanation:

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When it comes to people living at sea level,<em> the oxygen can easily pass through the lung membranes</em> due to <u>higher atmospheric pressure.</u> This doesn't require the body to build new RBCs. Therefore, the numbers of RBCs needed by people to thrive is lower than living at higher altitudes.

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3 years ago
Classify each change (which can be manipulated within the green box) according to its effect on the wavelength.
Nataly_w [17]

Answer:

Explanation:

The classification will be made into 3 categories, which are

Ones that shortens wavelengths

Ones that lengthens wavelengths

Ones that has no effect on wavelengths

Shortens wavelengths -> Increase frequency

Lengthens wavelengths -> Decrease frequency

No effect -> Increase amplitude, decrease amplitude, increase damping, decrease damping.

7 0
3 years ago
Responding to an alarm, a 765-N firefighter slides down a pole to the ground floor, 3.5 m below. The firefighter starts at rest
Afina-wow [57]

Answer:

Explanation:

Let acceleration of fall be a .

v² = u² + 2as

v = 3.8 m /s

u = 0

s = 3.5 m

3.8² = 0 + 2 x a x 3.5

a = 2.06 m /s²

Since this acceleration is less than g , an upward force is acting on the firefighter in the form of friction . Let this force be F . Let mass of the firefighter be m .

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4 0
2 years ago
Two circular holes, one larger than the other, are cut in the side of a large water tank whose top is open to the atmosphere. Ho
lidiya [134]

Answer:\frac{r_1}{r_2}=1.565

Explanation:

Given

two holes are made with different sizes

Hole 1 is large in size and hole 2 is small

If the volume flow rate of water is same for both the hole then small hole must be below the large hole because for same flow rate, velocity of water is large while cross-sectional area is small so it compensate to give same flow for both the holes.

Now for radius apply Bernoulli's theorem at hole 1 and 2

P_1+\rho gh_1=P_{atm}+\frac{1}{2}\rho v_1^2

P_2+\rho g6h_2=P_{atm}+\frac{1}{2}\rho v_2^2

if hole 1 is h distance below water surface then h_2=6h

and P_1=P_2=P_{atm}

Also v_1=\sqrt{2gh}

v_2=\sqrt{2g(6h)}

and Q=A_1v_1=A_2v_2

A=\pi r^2

thus \dfrac{r_1}{r_2}=\sqrt{\dfrac{v_2}{v_1}}

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\frac{r_1}{r_2}=1.565

5 0
3 years ago
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