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wolverine [178]
3 years ago
6

An automobile moving along a straight track changes its velocity from 40 m/s to 80 m/s in a distance of 200 m. What is the (cons

tant) acceleration of the vehicle during this time?
Question 13 options:
1) 8.0 m/s
2) 9.6 m/s
3) 12 m/s
4) 6.9 m/s
5) 0.20 m/s
...?
Physics
1 answer:
Yakvenalex [24]3 years ago
3 0
To calculate the acceleration we use a fundamental kinematic equation, which is expressed as:

<span>vf^2</span>=<span>vi^2</span>+2a<span>d

We can write it as follows:

a= (vf^2 - vi^2) / 2d
a = (80^2 - 40^2) / 2(200)
a = 12 m/s^2 ----> OPTION 3

Hope this answers the question. Have a nice day.</span>
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