1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zolol [24]
3 years ago
13

he Hobbits are building a watchtower so they can prepare to battle in case trolls decide to attack them. One Hobbit will always

be on the lookout and the Hobbits will prepare for battle as soon as the trolls are visible. The time, TTT, in minutes, that the Hobbits have to prepare for the attack of trolls kkk meters away is given by the function T(k)=\dfrac{k}{80}T(k)= 80 k ​ T, left parenthesis, k, right parenthesis, equals, start fraction, k, divided by, 80, end fraction. The visibility, VVV, in meters, that the Hobbits have from an mmm meter watch tower is given by the function V(m)=50mV(m)=50mV, left parenthesis, m, right parenthesis, equals, 50, m. Find an explicit expression that models the amount of time the Hobbits have to prepare for a troll attack given that the watchtower is mmm meters tall.
Physics
1 answer:
joja [24]3 years ago
4 0

Answer:

5m/8

Explanation:

Function T gives the time the Hobbits have to prepare for the attack, T(k), in minutes, as a function of troll's distance, k, in meters.

Function V gives visibility from the watchtower, V(m), in meters, as a function of the height of the watchtower, m, in meters.

Therefore, T(V(m)) will give the time the Hobbits have to prepare for the troll attack as a function of the height, m, of the watchtower.

We can input m into function V to obtain the visibility from watchtower, V(m), in meters. Since visibility indicates the distance you can see, this also gives the distance of the trolls. This can then be input into function T to obtain the time that the Hobbits have to prepare for a troll attack.

Let's find T(V(m)) by substituting the formula for V(m) into function T as shown below.

T(V(M))=T(50m)

=50m/80

We can simplify this as follows:

=50m/80

=5m/8

You might be interested in
Humpback whales sometimes catch fish by swimming rapidly in a circle, blowing a curtain of bubbles that confuses a school of fis
andre [41]

Answer:

1.2 x 10^4 N

Explanation:

The centripetal force of a body moving in a circle is given by:

Centripetal force = \frac{Mv^2}{r}

where M = mass of the object, v = velocity with which the object is moving, and r = radius of the circle.

In this case, M = 25,000 kg, v = 2.0 m/s, and r = 8.2 m. Hence;

Centripetal force generated by the whale = 25,000 x 2^2/8.2

                                            = 12,195.12 N = 1.2 x 10^4 N to two significant digits.

8 0
3 years ago
A 20 MHz carrier is frequency modulated by a sinusoidal signal such that the maximum frequency deviation is 100kHz. Calculate th
Ivan

Answer:

Idk

Explanation:

6 0
3 years ago
How far apart are the fringes in the center of the pattern on a screen 4.3 m away? Express your answer to two significant figure
attashe74 [19]

Answer:

d = \frac{nLembda}{sin(theta)}

Explanation:

This comes from diffrection pattern equation used to locate fringe pattern, i will explain every variable in it here.

n = order of fringe = 0 1 2 3 .. and negative integars as well.

d is sacing between slits.

Theta = angle at which light-Ray is directed towards fringe.

It appears that the distance between consectice fringes would same as the distance between two slits 'd'.

therefore calculating that distance should give us the distance between two fringe patters.

Note we don't use transversal seperation distance here.

4 0
3 years ago
How we will measure centimeters
Bingel [31]

Answer:

  • .

Explanation:

——»To measure centimeters, we can use ruler.

  • Use a ruler with the side marked either cm or mm. Align the edge of the object with the first centimeter line on the ruler, then find the length in whole centimeters, or the larger numbers on the ruler.
7 0
2 years ago
What is the frequency of an X-ray with wavelength 0.13 nm ? Assume that the wave travels in free space. Express your answer to t
dem82 [27]

Answer:

Frequency, f=2.30\times 10^{18}\ Hz

Explanation:

Given that,

The wavelength of the x-rays, \lambda=0.13\ nm=0.13\times 10^{-9}\ m

We need to find the frequency of an x-ray. All electromagnetic wave travel with a speed of light. It is given by the formula as :

c=f\lambda

f is the frequency

f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{0.13\times 10^{-9}}\\\\f=2.30\times 10^{18}\ Hz

So, the frequency of an x-ray is 2.30\times 10^{18}\ Hz. Hence, this is the required solution.

5 0
3 years ago
Other questions:
  • A steel cylinder has a length of 2.16 in, a radius of 0.22 in, anda mass of 41 g. what is the density of the steel in g/cm^3?
    5·1 answer
  • How are potential and kinetic energy related to one another?
    15·1 answer
  • Race: Blythe and Geoff compete in a 1-km race. Blythe’s strategy is to run the first 600 m of the race at a constant speed of 4
    13·1 answer
  • Which is not an issue with waste from nuclear energy?
    5·1 answer
  • What is the purpose of a hypothesis?
    11·2 answers
  • State 2 defects of primary cells​
    5·1 answer
  • How much kinetic energy do you think a ball will have if it were dropped from a 2-m shelf
    10·2 answers
  • A boat floats up and down with the time period of two seconds as the wave passes under it. What is the frequency ?
    8·1 answer
  • Which Lunar Feature isn't a darker region? *<br> Lake<br> Ocean<br> Highland<br> Sea
    5·1 answer
  • Lou’s latest invention, aimed at urban dog owners, is the X-R-Leash. It is made of a rubber-like material that exerts a force Fx
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!