All categories

4 years ago

How would I find the answer to this question

Mathematics

2 answers:

Stels [109]4 years ago

8 0

2:5 is the answer I’m 100% sure it is jajajjajaj

sweet-ann [11.9K]4 years ago

4 0

The answer would be 2:5

you first have to add all the cards together to find out how many cards you have total. In this case there are 60 cards. So your first starting number would be 24 : 60 this would need to be simplified by figuring out what is the largest number both numbers can be divided by equally. In this case 12, so your final answer would be a 2 to 5 chance of pulling a blue card. Hope this helps.

You might be interested in

Help me out please?? Tysvm!

Kamila [148]

Answer:

910 mL = 0.91 L

9.1 L = 9,100 mL

0.901 kL = 901 L

91 L = 0.091 kL

90.1 L = 90,100 mL

9,010 mL = 9.01 L

Step-by-step explanation:

6 0

3 years ago

Here is my question i need help answering it

ollegr [7]

Ur answer will be C… basically u make the equation equal to zero and then use the quadratic formula to find ur answers…. x = -3 and 9

5 0

2 years ago

adoni [48]

Step-by-step explanation:

CCTV cameras in a bit more of the day I will have a great time and where is the only thing that has to do with it

7 0

3 years ago

What is an equation of the line that passes through the points (-4,-2)<br> and (8, 1)?

stiv31 [10]

Answer:

y=1/4x-1

Step-by-step explanation:

7 0

3 years ago

The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.

pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

$m_{1}\times m_{2}=-1$

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

$m_{normal} \times m_{tangent}=-1$

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

$m=\frac{y_2-y_1}{x_2-x_1}$

$=\frac{8-4}{-6+6}$

= ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0

3 years ago