Answer:
minimum sight distance = 699 ft
Explanation:
given data
road lane = 4 divided road
median width = 12 ft
grade road = 5%
solution
we take here time gap factor for minor road vehicle when enter to major road from table
time gap = 8.1 sec
and for median width of 12 ft
time gap = 8.2 + 0.7 ( 1 +
)
time gap = 9.5 second
so minimum sight distance will be
minimum sight distance = 1.47 × design speed × time gap
minimum sight distance = 1.47 × 50 × 9.5
minimum sight distance = 699 ft
Answer:
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Forces exerted by the jet on the plate is=3976N
<h3>How to calculate forces exerted by the jet on the plate?</h3>
A force is an effect that can change the motion of an object. A force can generate an object with mass to change its velocity, i.e., to accelerate. Force can also be explained intuitively as a push or a pull. A force has both volume and direction, making it a vector amount.
A jet of water 75m in diameter
velocity = 30m/s
The forces exerted by the jet on the plate is
F=1000×44178×10^-3×30²
=3976N
the jet on the plate work done by Is zero .
To learn more about Force, refer
brainly.com/question/12970081
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