Answer:
<u>Option-(A)</u>
Explanation:
<u>Typical applications for the high carbon steels includes the following;</u>
It is heat treatable, relatively large combinations of mechanical characteristics. Typical applications: railway wheels and tracks, gears, crankshafts, and machine parts.
Answer:
Welcome to Gboard clipboard, any text that you copy will be saved here.
Explanation:
Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.
Answer:
touching
Explanation:
The backrest of the seat should be tilted back ever so slightly, and when turning the steering wheel your shoulders should remain in contact with the seat – rather than hunched forward.
Answer:
# Program is written in Python Programming Language
# Comments are used for explanatory purpose
# Program starts here
# Accept input
Steps = input (Number of Steps: ")
# Calculate distance
distance = float(2000) * float(steps)
#Print Formatted Result
print('%0.2f' % distance)
# End of Program
.--------
The above program converts number of steps to miles.
At line 5, the number of steps is inputted and stored in variable named Steps.
At line 6, the number of miles is calculated by multiplying 2000 by the content of variable Steps
The result is printed at line 8
Answer:
%Reduction in area = 73.41%
%Reduction in elongation = 42.20%
Explanation:
Given
Original diameter = 12.8 mm
Gauge length = 50.80mm
Diameter at the point of fracture = 6.60 mm (0.260 in.)
Fractured gauge length = 72.14 mm.
%Reduction in Area is given as:
((do/2)² - (d1/2)²)/(do/2)²
Calculating percent reduction in area
do = 12.8mm, d1 = 6.6mm
So,
%RA = ((12.8/2)² - 6.6/2)²)/(12.8/2)²
%RA = 0.734130859375
%RA = 73.41%
Calculating percent reduction in elongation
%Reduction in elongation is given as:
((do) - (d1))/(d1)
do = 72.14mm, d1 = 50.80mm
So,
%RA = ((72.24) - (50.80))/(50.80)
%RA = 0.422047244094488
%RA = 42.20%
