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3 years ago

I'll mark the Brainliest answer and You'll receive 20 POINTS!

Mathematics

1 answer:

alina1380 [7]3 years ago

6 0

A decagon has 10 sides.

The sum of the interior angles is found using the formula S = (n-2)*180, where n is the number of sides.

The total sum of the interior angles of a decagon would be:

(10-2) *180 = 8 * 180 = 1440 degrees.

Now to find the measure of each interior angle, divide the total sum by the number of sides:

1440 / 10 = 144

Each angle is 144 degrees.

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Pi High School ordered 40 science books. The next week, the school ordered 30 algebra books. The bill for the first order was $3

maria [59]

Answer:

Each algebra book costs $60.

Step-by-step explanation:

A=bill for algebra books; S=bill for science books=A+$360

S+A=$3960 Substitute for S

A+$360+A=$3960 Subtract $360 from each side.

2A=$3600 Divide each side by 2.

A=$1800 The order for 30 algebra books cost $1800.

Individual book=A/30

individual book=$1800/30=$60 ANSWER: Each algebra book cost $60.

4 0

3 years ago

What number has the same value as 14 tens?

Dovator [93]

140 because 14 ten times is 140 and thats the same value as 14 tens

5 0

3 years ago

Read 2 more answers

The sum of a number wand 4 is more than -12.

Mazyrski [523]

The answer is w + 4 > -12

4 0

3 years ago

The sum of prime number less than x is 58 find an integer value for x

s344n2d4d5 [400]

Answer:

but it can be 18 too

cuz the q doesn't tell us that the value of x has to be a prime no.

Step-by-step explanation:

2+3+5+7+11+13+17=58

6 0

3 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

4 0

3 years ago