Od. 0-0 does not pair of the Molecules bid it’s polar bond due to certain pairs of molecules not being present within its presentations
moles Cu produced : 0.002
<h3>Further explanation</h3>
Concentration of copper sulfate (CuSO₄) : 0.319 g/dm³
MW CuSO₄ :
![\tt =63.5+32+4\times 16=159.5~g/mol](https://tex.z-dn.net/?f=%5Ctt%20%3D63.5%2B32%2B4%5Ctimes%2016%3D159.5~g%2Fmol)
mol CuSO₄ /dm³ :
![\tt \dfrac{0.319}{159.5}=0.002](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7B0.319%7D%7B159.5%7D%3D0.002)
CuSO₄⇒Cu²⁺ + SO₄²⁻
mol Cu : mol CuSO₄ = 1 : 1 , so mol Cu²⁺=0.002
The equilibrium constant of the reaction is represented by the symbol K. Thus, option C is the correct and accurate statement about the equilibrium constant.
<h3>What is the equilibrium constant?</h3>
The equilibrium constant is a representation of the concentration of the products and the reactants of the reaction that is raised to the powers through their stoichiometry coefficient.
Its value varies and changes at different temperatures and is not always less than 1. The equilibrium constant is the ratio of the coefficient of the products to reactants.
Therefore, option C. equilibrium constant is represented by K is true.
Learn more about the equilibrium constant here:
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Taking into account the definition of molarity, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2
.
<h3>Definition of molarity</h3>
Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
![molarity=\frac{number of moles}{volume}](https://tex.z-dn.net/?f=molarity%3D%5Cfrac%7Bnumber%20of%20moles%7D%7Bvolume%7D)
Molarity is expressed in units
.
<h3>Molarity in this case</h3>
In this case, you have:
- number of moles= 0.2 moles
- volume= 100 mL= 0.1 L
Replacing in the definition of molarity:
![molarity=\frac{0.2 mole}{0.1 L}](https://tex.z-dn.net/?f=molarity%3D%5Cfrac%7B0.2%20mole%7D%7B0.1%20L%7D)
Solving:
<u><em>molarity= 2 </em></u>![\frac{moles}{liter}](https://tex.z-dn.net/?f=%5Cfrac%7Bmoles%7D%7Bliter%7D)
Finally, the molarity of a solution prepared by dissolving 0.2 mol sucrose in enough water to make a 100 mL solution is 2
.
Learn more about molarity:
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