Answer:
The answer to your question is: 69.6 %
Explanation:
Freon -112 (C₂Cl₄F₂)
MW = (12 x 2) + (35.5 x 4) + (19 x 2)
= 24 + 142 + 38
= 204 g
204 g of C₂Cl₄F₂ ----------------- 100%
142 g ----------------- x
x = (142 x 100 ) / 204
x = 69.6 %
Answer:
C₂ = 0.149 M
Explanation:
Given data:
Initial concentration = 0.407 M
Initial volume = 2.56 L
Final volume = 7.005 L
Final concentration = ?
Solution:
Formula:
C₁V₁ = C₂V₂
C₁ = Initial concentration
V₁ = Initial volume
C₂ = Final concentration
V₂ =Final volume
Now we will put the values.
0.407 M × 2.56 L = C₂ × 7.005 L
1.042 = C₂ × 7.005 L
C₂ = 1.042 M.L / 7.005 L
C₂ = 0.149 M
I'm not sure on this I'm sorry I can't help you I wish I could!
