Answer:
4.36 rad/s
Explanation:
Radius of platform r = 2.97 m
rotational inertia I = 358 kg·m^2
Initial angular speed w = 1.96 rad/s
Mass of student m = 69.5 kg
Rotational inertia of student at the rim = mr^2 = 69.5 x 2.97^2 = 613.05 kg.m^2
Therefore initial rotational momentum of system = w( Ip + Is)
= 1.96 x (358 + 613.05)
= 1903.258 kg.rad.m^2/s
When she walks to a radius of 1.06 m
I = mr^2 = 69.5 x 1.06^2 = 78.09 kg·m^2
Rotational momentuem of system = w(358 + 78.09) = 436.09w
Due to conservation of momentum, we equate both momenta
436.09w = 1903.258
w = 4.36 rad/s
<span> The masses have no inertia about their own CM, and "the object" is the two masses. </span>
<span>1. Icm (at point A) = 2mr^2
hope this helps</span>
<u><em>Answer:</em></u>
Momentum of the skier is 350 Kg.m/sec
<u><em>Explanation:</em></u>
<u>Momentum of a body can be calculated using the following rule:</u>
P = m * v
<u>where:</u>
P is the momentum of the body
m is the mass of the body given as 70 Kg
v is the velocity of the body given as 5 m/sec
<u>Substitute with the givens in the above rule to get the momentum of the skier as follows:</u>
P = m * v
P = 70 * 5
P = 350 Kg.m/sec
Hope this helps :)