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atroni [7]
3 years ago
8

Section 2.2

Physics
1 answer:
Feliz [49]3 years ago
6 0

Answer:

Speed changes at the rate of 24 m/s for each second over time.

Explanation:

We are told the object's acceleration is equal to 24 m/s²

Now we know that acceleration can also be defined as the rate of change of speed with time. Also speed has a unit known as m/s.

Thus, we can rephrase the acceleration in this question to mean;

Speed changes at the rate of 24 m/s for every second with time.

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how much heat is required to raise the temperature 500 of song of iron from 50°to 250°c? (take c=480j/kg°c)​
Mars2501 [29]

Answer:

Explanation:

523 degrees

5 0
2 years ago
Please help!
julsineya [31]

Answer:

Answer:

3 g/cm          

Explanation:

Mass of stone = 30 g

Initial volume of cylinder = 50 cm

Increased volume = 60 cm

Volume = 60-50

= 10 cm

Density of stone = Mass/Volume

= 30/10

= 3 g/ml            as 1 ml = 1 cm

= 3 g/ml          

Explanation:

6 0
2 years ago
How many watts are used when 6000 joules of energy are consumed in 5 hours?
Ray Of Light [21]
Power = energy / time
Time should be in seconds
5 hours = 5 × 60 minutes = 5 × 60 ×60 seconds = 18000 s
Power = 6000/18000 = 0.333 W

Hope it helped!
7 0
3 years ago
You are observing a spacecraft moving in a circular orbit of radius 100,000 km around a distant planet. You happen to be located
Natalija [7]

To solve this problem we will apply the concepts related to centripetal acceleration, which will be the same - by balance - to the force of gravity on the body. To find this acceleration we must first find the orbital velocity through the Doppler formulas for the given periodic signals. In this way:

v_{o} = c (\frac{\lambda_{max}-\bar{\lambda}}{\bar{\lambda}}})

Here,

v_{o} =  Orbital Velocity

\lambda_{max} = Maximal Wavelength

\bar{\lambda}} = Average Wavelength

c = Speed of light

Replacing with our values we have that,

v_{o} = (3*10^5) (\frac{3.00036-3}{3})

<em>Note that the average signal is 3.000000m</em>

v_o = 36 km/s

Now using the definition about centripetal acceleration we have,

a_c = \frac{v^2}{r}

Here,

v = Orbit Velocity

r = Radius of Orbit

Replacing with our values,

a = \frac{(36km/s)^2}{100000km}

a= 0.01296km/s^2

a = 12.96m/s^2

Applying Newton's equation for acceleration due to gravity,

a =\frac{GM}{r^2}

Here,

G = Universal gravitational constant

M = Mass of the planet

r = Orbit

The acceleration due to gravity is the same as the previous centripetal acceleration by equilibrium, then rearranging to find the mass we have,

M = \frac{ar^2}{G}

M = \frac{(12.96)(100000000)^2}{ 6.67*10^{-11}}

M = 1.943028*10^{27}kg

Therefore the mass of the planet is 1.943028*10^{27}kg

7 0
3 years ago
What did ancient astronomers think areas of the moon called mares might be?
Bumek [7]

The ancient astronomers think areas of the moon called mares might be Seas.

Option D  

<u>Explanation</u>:

The surface area of Earth's moon is dark, large, and is basaltic plains which are formed by ancient volcanic eruptions. They were dubbed as Maria, "ancient astronomers" who misunderstood them as actual seas. They are less reflective than highlands. Due to their iron-rich composition, they tend to appear dark from the naked eye. The Maria cover approximately about 16% of surface mostly on side that is visible from Earth. The few Maria on side that is too far are much smaller and residing mostly in very large craters. The ancient astronomers mistook the surface area as look like actual seas.

4 0
3 years ago
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