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atroni [7]
2 years ago
8

Section 2.2

Physics
1 answer:
Feliz [49]2 years ago
6 0

Answer:

Speed changes at the rate of 24 m/s for each second over time.

Explanation:

We are told the object's acceleration is equal to 24 m/s²

Now we know that acceleration can also be defined as the rate of change of speed with time. Also speed has a unit known as m/s.

Thus, we can rephrase the acceleration in this question to mean;

Speed changes at the rate of 24 m/s for every second with time.

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The velocity of a wave is the product of the frequency and the
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Answer:

The answer is A. wavelength

Based on the wavespeed formula v=fλ

Velocity of wave is the product of <em>frequency(f)</em> and <em>wavelength(λ)</em>

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What is the total resistance of 3 resistors of 3ohms added together in series?
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In series, you just add them: R1 + R2 + R3 = Total R
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Homework: Making Connections to Science Ideas
natita [175]

The patterns that can be looked for when studying science topic include the use of data or carrying out an experiment.

<h3>How to illustrate the information?</h3>

It should be noted that patterns are regular and intelligible forms or sequences that can be found in nature. Based on the information, scientific questions may be generated when scientists want to observe a pattern of events.

It should be noted that when scientists want to observe a pattern of events or

when something does not match an established pattern, scientists can use patterns to classify objects or phenomena into groups.

Therefore, the patterns that can be looked for when studying science topic include the use of data or carrying out an experiment.

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1 year ago
PLZ HELP FAST!!!!!!!!!Which characteristics describe a maritime polar air mass? A.cold and humid air B.cold and dry air C.warm a
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2 years ago
At what angle two forces P + Q and (P - Q) act so that their resultant is :
stiv31 [10]

Use resultant formula

\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\theta}}

So

#1

A be p+q and B be p-q

\\ \rm\Rrightarrow R=\sqrt{3p^2+q^2}

\\ \rm\Rrightarrow \sqrt{(p+q)^2+(p-q)^2+2(p+q)(p-q)cos\alpha}=\sqrt{3p^2+q^2}

\\ \rm\Rrightarrow 2p^2+2q^2+2(p^2-q^2)cos\alpha=3p^2+q^2

\\ \rm\Rrightarrow 2cos\alpha=1

\\ \rm\Rrightarrow cos\alpha=\dfrac{1}{2}

\\ \rm\Rrightarrow \alpha=\dfrac{\pi}{3}

#2

\\ \rm\Rrightarrow 2(p^2+q^2)+2(p^2-q^2)cos\beta=2(p^2+q^2)

\\ \rm\Rrightarrow 2cos\beta=0

\\ \rm\Rrightarrow cos\beta=0

\\ \rm\Rrightarrow \beta=\dfrac{\pi}{2}

#3

\\ \rm\Rrightarrow 2(p^2+q^2)+2(p^2-q^2)cos\gamma=p^2+q^2

\\ \rm\Rrightarrow 2(p^2-q^2)cos\gamma=-(p^2+q^2)

\\ \rm\Rrightarrow cos\gamma =\dfrac{q^2-p^2}{2(p^2-q^2)}

\\ \rm\Rrightarrow \gamma=cos^{-1}\left(\dfrac{q^2-p^2}{2(p^2+q^2)}\right)

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2 years ago
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