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sweet [91]
2 years ago
11

How will creat thunderstrom​

Physics
1 answer:
emmasim [6.3K]2 years ago
3 0

Answer:

the air has to be unstable as well as it needs to be moved upwards.

Explanation:

it needs to be moved upwards and also needs to have unstable air.

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Write comparison between Electrical Circuit and Magnetic Circuit.
Anarel [89]

<u>electrial</u><u> </u>

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<u>magnetic</u><u> </u><u>circuit</u><u> </u>

<u>In the magnetic circuit, magnetic flux flows through the closed path</u>

7 0
3 years ago
In a scientific experiment, what is the purpose of a procedure?
djyliett [7]

Answer:

The procedure is the plan for how you will conduct your experiment.

Explanation:

7 0
3 years ago
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A wind turbine is rotating at 15 rpm under steady winds flowing through the turbine at a rate of 42,000 kg/s. The tip velocity o
zzz [600]

Answer:

a) 5.22 m/s

b) 31.4 %

Explanation:

f = rotating speed = 15 rpm = 15/60 =0.25 rps

m = Mass flow rate of air = 42000 kg/s

v = Tip velocity = 250 km/h = 250/3.6 = 69.44 m/s

W = Work output = 180 kW

A = Swept area of wind turbine

r = Radius of wind turbine

η = Efficiency

r=\frac{v}{2\pi f}\\\Rightarrow r=\frac{250\div 3.6}{2\pi 0.25}=\frac{250}{1.8\pi}

A=\pi r^2\\\Rightarrow A=\pi\left(\frac{250}{1.8\pi}\right)^2\\\Rightarrow A=\left(\frac{250}{1.8}\right)^2\frac{1}{\pi}

m=\rho V\\\Rightarrow m=\rho vA\\\Rightarrow v=\frac{m}{\rho A}\\\Rightarrow v=\frac{42000}{1.31 \left(\frac{250}{1.8}\right)^2\frac{1}{\pi}}\\\Rightarrow v=5.22\ m/s

∴ The average velocity of the air is 5.22 m/s

E=m\frac{v^2}{2}=42000\frac{5.22^2}{2}\\\Rightarrow E=572538.92

\eta=\frac{W}{E}=\frac{180000}{572538.92}\\\Rightarrow \eta =0.314

∴ Conversion efficiency of the turbine is 0.314 or 31.4 %

7 0
3 years ago
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A 3.0 kg ball moving at 8 m/s to the right collides with a 1.0 kilogram ball at rest. After the collision, the 3
amid [387]

Let m₁ = 3.0 kg and v₁ = + 8 m/s (so right is positive), and m₂ = 1.0 kg and v₂ = 0. The total momentum of the two balls before and after collision is conserved, so

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

where v₁' = + 5 m/s and v₂' are the velocities of the two balls after colliding, so

(3.0 kg) (8 m/s) = (3.0 kg) (5 m/s) + (1.0 kg) v₂'

Solve for v₂' :

24 kg•m/s = 15 kg•m/s + (1.0 kg) v₂'

(1.0 kg) v₂' = 9 kg•m/s

v₂' = (9 kg•m/s) / (1.0 kg)

v₂' = + 9 m/s

which is to say, the second ball is given a speed of 9 m/s to the right after colliding with the first ball.

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3 years ago
Which statement best compares these two waves
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“Wave-B is every bit as invisible as Wave-A is.”
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