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3 years ago

Someone please please help me with this math problem I’m really bad at graphs

Mathematics

2 answers:

nataly862011 [7]3 years ago

8 0

Answer:

$y + 2 = - (x - 4)$

Step-by-step explanation:

The graph passes through: (0,2) and (2,0)

The slope is

$\frac{0 - 2}{2 - 0} = - 1$

The equation of the line in point-slope form is given by:

$y-y_1=m(x-x_1)$

The graph passes through (4,-2).

We substitute the slope and this point to get:

$y - - 2 = - 1(x - 4)$

$y + 2 = - (x - 4)$

The first option is correct

VikaD [51]3 years ago

3 0

The answer is A, I hope my work really helpful

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Pls answer asap :)

dezoksy [38]

Answer:

one fourth

Step-by-step explanation:

8 0

3 years ago

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Find the indefinite integral. (Note: Solve by the simplest method—not all require integration by parts. Use C for the constant o

umka2103 [35]

Answer:

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2 ln⁡(1+x^2 )+C

Step-by-step explanation:

∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗

Let 1st=arctan⁡(x)

And 2nd=1

∫▒〖arctan⁡(x).1 dx=arctan⁡(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗

As we know that

derivative of arctan(x)=1/(1+x^2 )

∫▒〖1 dx〗=x

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1

Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now

Let 1+x^2=u

du=2xdx

Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get

1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)

1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)

1/2 ∫▒(2xdx/u) =1/2 ln⁡(u)+C

1/2 ∫▒(2xdx/u) =1/2 ln⁡(1+x^2 )+C

Putting values in Eq1 we get

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2 ln⁡(1+x^2 )+C (required soultion)

3 0

3 years ago

Read 2 more answers

State the domain and range of the given relation

GuDViN [60]

Answer:

work is shown and pictured

5 0

3 years ago

WHY IS THIS GETTING DELETED?? I NEED HELP

aliina [53]

If this exact question is repeatedly deleted, it's probably because of the ambiguity of the given equation. I see two likely interpretations, for instance:

$\dfrac{(5\times5)^k}{5^{-8}} = 5^3$

$\dfrac{5\times 5^k}{5^{-8}} = 5^3$

If the first one is what you intended, then

$\dfrac{(5\times5)^k}{5^{-8}} = \dfrac{(5^2)^k}{5^{-8}} = \dfrac{5^{2k}}{5^{-8}} = 5^{2k-(-8)} = 5^{2k+8} = 5^3$

and it follows that

2k + 8 = 3 ==> 2k = -5 ==> k = -5/2

If you meant the second one, then

$\dfrac{5\times 5^k}{5^{-8}} = \dfrac{5^1\times5^k}{5^{-8}} = \dfrac{5^{k+1}}{5^{-8}} = 5^{k+1-(-8)} = 5^{k+9} = 5^3$

which would give

k + 9 = 3 ==> k = -6

And for all I know, you might have meant some other alternative... When you can, you should include a picture of your problem.

3 0

3 years ago

Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots. If this player shoots twi

Kipish [7]

Answer:

The probability of scoring two goals in both times is 0.137 or 13.7%

Step-by-step explanation:

Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots.

So $P(A)=0.63$

Hence, the probability of getting success in his shoots will be,

$P(A^c)=1-P(A)=1-0.63=0.37$

The probability of scoring two goals in both times is,

$=P(A^c)\cdot P(A^c)$

$=0.37\times 0.37$

$=0.137$

$=13.7\%$

7 0

3 years ago

Read 2 more answers