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Ulleksa [173]
3 years ago
11

You are given sodium acetate, 1M HCl, NaHCO3 and Na2CO3. Determine which of these four you would need and then show calculations

to make buffer pH = 4.7 by method 2. Assume making 100 mls of a 0.1 M buffer.
Neutralization of a portion of the weak base with sufficient strong acid to give the desired ratio, [A- ]/[HA]: Na+ + A- + HCl → HA + Na+ + Cl-

I've been having a lot of trouble going step by step with this one. If you could really explain the logic behind each step it would be very much appreciated!! I'm also confused about the ka value. Am I just supposed to look that up? Thank you so much for your time!
Chemistry
1 answer:
Anvisha [2.4K]3 years ago
7 0

Answer:

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Explanation:

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Which element would have the greater difference between the first ionization energy and the second ionization energy
andrew-mc [135]

Answer:

Lithium has the greatest difference between its first and second ionization energies.

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3 years ago
An equilibrium mixture contains 0.750 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the
sasho [114]

1.302  moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}

While the equilibrium constant is based on partial pressure

\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}

The value of Kp and Kc can be linked to the formula '

\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}

R = gas constant = 0.0821 L.atm / mol.K

=n = number of product coefficients-number of reactant coefficients

An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O

  • We determine Kc (constant concentration)

\displaystyle Kc=\frac{0.75.0.75}{0.2.0.2}\\\\Kc=14.1

  • the amount of carbon monoxide to 0.300 mol

Reaction :

                CO +H₂O ⇔ CO₂ + H₂

initially      0.2   0.2       0.75+x  0.75

reaction    0.1    0.1        0.1         0.1

product     0.3   0.3       0.65+x    0.65

\displaystyle Kc=\frac{(0.650+x)(0.65)}{0.3.0.3}\\\\14.1(0.09)=0.4225+0.65x\\\\1.269-0.4225=0.65x\\\\0.8465=0.65x\\\\x=1.302

<h3>Learn more</h3>

an equilibrium constant brainly.com/question/9173805

brainly.com/question/1109930

Calculate the value of the equilibrium constant, Kc

brainly.com/question/3612827

Concentration of hi at equilibrium

brainly.com/question/8962129

Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient

3 0
4 years ago
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What happens to the ground particles when they’re hit by sunlight
ExtremeBDS [4]

Answer:

The Earth absorbs most of the energy reaching its surface

Explanation:

a small fraction is reflected. In total approximately 70% of incoming radiation is absorbed by the atmosphere and the Earth's surface while around 30% is reflected back to space and does not heat the surface.

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A scientist took notes about the fossil in the picture.
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b. forest ....

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A saline solution contains 1.1% NaCl by mass. How much NaCl is present in 96.3 g of this solution
timurjin [86]

Answer:

= 1.0593 g

Explanation:

1.1% NaCl by mass, means;

1.1 g per 100 g = 0.011

Therefore; the amount of NaCl present in 93.6 g of the solution is;

= 0.011 × 96.3 g

<u>= 1.0593 g</u>

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4 years ago
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