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Ratling [72]
2 years ago
5

Describe an element and a compound. Compare and contrast their similarities and differences. Identify how elements are related t

o compounds. Be sure to include the following key vocabulary terms: Pure substance, chemical symbol, chemical formula.
Chemistry
1 answer:
Alenkasestr [34]2 years ago
4 0

Answer:

<u>»</u><u> </u><u>Similarities</u><u> </u><u>:</u>

☑ They both react by chemical means, to produce either an element or compound as the end product of the chemical reaction.

• Take an example of Magnesium reacting with cold water:

{ \rm{Mg_{(s)}  + 2H _{2} O _{(l)}  → Mg(OH)_{2(aq)} + H_{2(g)}}}

• If it reacts with steam:

{ \rm{Mg _{(s)}  + H _{2} O_{(l)} → MgO_{(s)} + H_{2(g)}}}

• [ Element: <em>Magnesium</em><em> </em>and Compound: <em>Water</em><em> </em>]

They are both classified under atomic substances cause they are made up of microscopic molecules known as atoms.

☑ They are both formed up by microscopic substances known as atoms.

<u>»</u><u> </u><u>Differences</u><u> </u><u>:</u>

☑ Compounds generally have higher molecular masses than elements.

☑ Compounds are formed through bonding by elements while elements can naturally exist or formed by extraction, purification and concentration

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In their notebook you see that it takes 9 hours for a sixth of a 0.5M solution of BC2 to react. Unfortunately, you have somewher
trasher [3.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration of BC_2 that should used originally is C_Z_o = 0.4492M

Explanation:

     From the question we are told that

         The necessary elementary step is  

                  2BC_2 ----->4C + B_2

          The  time taken for sixth of 0.5 M of reactant to react t = 9 hr

           The time available is t_a = 3.5 hr

             The desired concentration to  remain C  = 0.42M

Let Z be the reactant ,   Y be the first product and X the second product

Generally the elementary rate  law is mathematically as

                    -r_Z = kC_Z^2 = - \frac{d C_Z}{dt}

Where k is the rate constant ,  C_Z is the concentration of Z

From the elementary rate law we see that the reaction is second order (This because the concentration of the reactant is raised to power 2 )

 For second  order reaction

            \frac{1}{C_Z}  - \frac{1}{C_Z_o}  = kt

Where C_Z_o is the initial concentration of Z which a value of   C_Z_o = 0.5M

       From the question we are told that it take  9 hours  for the concentration of  the reactant to become

                 C_Z =  C_Z_o - \frac{1}{6}  C_Z_o

                  C_Z = 0.5  - \frac{0.5}{6}

                       = 0.4167 M

So      

                     \frac{1}{0.4167}  - \frac{1}{0.50}  =  9 k

                          0.400 = 9 k

                =>    k = 0.044\  L/ mol \cdot hr^{-1}

  For   C_Z = 0.42M

                \frac{1}{0.42} - \frac{1}{C_Z_o}  = 3.5 * 0.044

                2.38 -  0.154  =    \frac{1}{C_Z_o}

                           2.226  =    \frac{1}{C_Z_o}

                            C_Z_o = \frac{1}{2.226}

                             C_Z_o = 0.4492M

                       

           

             

         

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Answer:

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The isomers of butane are

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b) t-butane

The structures are shown in the figure.

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The structures are shown in figure.

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