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Ratling [72]
2 years ago
5

Describe an element and a compound. Compare and contrast their similarities and differences. Identify how elements are related t

o compounds. Be sure to include the following key vocabulary terms: Pure substance, chemical symbol, chemical formula.
Chemistry
1 answer:
Alenkasestr [34]2 years ago
4 0

Answer:

<u>»</u><u> </u><u>Similarities</u><u> </u><u>:</u>

☑ They both react by chemical means, to produce either an element or compound as the end product of the chemical reaction.

• Take an example of Magnesium reacting with cold water:

{ \rm{Mg_{(s)}  + 2H _{2} O _{(l)}  → Mg(OH)_{2(aq)} + H_{2(g)}}}

• If it reacts with steam:

{ \rm{Mg _{(s)}  + H _{2} O_{(l)} → MgO_{(s)} + H_{2(g)}}}

• [ Element: <em>Magnesium</em><em> </em>and Compound: <em>Water</em><em> </em>]

They are both classified under atomic substances cause they are made up of microscopic molecules known as atoms.

☑ They are both formed up by microscopic substances known as atoms.

<u>»</u><u> </u><u>Differences</u><u> </u><u>:</u>

☑ Compounds generally have higher molecular masses than elements.

☑ Compounds are formed through bonding by elements while elements can naturally exist or formed by extraction, purification and concentration

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it is (a) USDA certification

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Mass
DiKsa [7]

The molecular formula =C₆H₁₂O₆

<h3>Further explanation</h3>

Given

6.00 g of a certain compound X

The molecular molar mass of 180. g/mol

CO₂=8.8 g

H₂O=3.6 g

Required

The molecular formula

Solution

mass C in CO₂ :

= 1.12/44 x 8.8

= 2.4 g

mass H in H₂O :

= 2.1/18 x 3.6

= 0.4 g

Mass O in compound :

= 6-(2.4+0.4)

= 3.2 g

Mol ratio C : H : O

= 2.4/12 : 0.4/1 : 3.2/16

= 0.2 : 0.4 : 0.2

= 1 : 2 : 1

The empirical formula : CH₂O

(CH₂O)n=180 g/mol

(12+2+16)n=180

(30)n=180

n=6

(CH₂O)₆=C₆H₁₂O₆

7 0
3 years ago
Which of the following are properties of solution?
DerKrebs [107]
Point of the graph because it’s the point
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3 years ago
NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a
Tanya [424]

Answer:

A = 0.023 m

Explanation:

The relation between the frequency of a radiation and its wavelength is given by the following expression.

where,

c is the speed of light (it has a constant value of 3.00 x 108 m/s)

A is the wavelength of the radiation v is the frequency of the radiation

In this case, the frequency is 13 GHz = 13 x

10° Hz = 13 x 1o° s-

The wavelength associated with this frequency is:

A = c/v = (3.00 x 10° m/s)/(13 x 10° s-") = 0.023

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2 years ago
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