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hoa [83]
3 years ago
12

Help me help me please

Chemistry
2 answers:
fgiga [73]3 years ago
7 0
I think the answer is wind
Vadim26 [7]3 years ago
4 0

Answer:

C. wind

Explanation:

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How many grams of glucose are needed to prepare 144.3 mL of a 1.4%(m/v) glucose solution?
Montano1993 [528]

Answer:

2.0202 grams

Explanation:

1.4% (m/v) glucose solution means: 1.4g glucose/100mL solution.

so ?g glucose = 144.3 mL soln

Now apply the conversion factor, and you have:

?g glucose = 144.3mL soln x (1.4g glucose/100mL soln).

so you have (144.3x1.4/100) g glucose= 2.0202 grams

6 0
3 years ago
Read 2 more answers
A. 1720 kJ<br> B. 125.6 kJ<br> C. 3440 kJ<br> D. 4730 kJ
Feliz [49]

Answer:

Q = 3440Kj

Explanation:

Given data:

Mass of gold = 2kg

Latent heat of vaporization = 1720 Kj/Kg

Energy required to vaporize 2kg gold = ?

Solution:

Equation

Q= mLvap

It is given that heat required to vaporize the one kilogram gold is 1720 Kj thus, for 2 kg

by putting values,

Q= 2kg ×  1720 Kj/Kg

Q = 3440Kj

7 0
3 years ago
Which two large landmasses formed when Pangaea first started to separate?
PilotLPTM [1.2K]

Answer:

Laurasia and Gondwanaland

Explanation:

7 0
3 years ago
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Which of the following statements is true? Choose one: A. Bronze was used as early as 4000 B.C.E. to replace less-desirable iron
Verizon [17]

Answer:

B.Bronze is harder than copper, so it retains a cutting edge sharper than that of copper.

Explanation:

The importance of bronze in the history of the human kind can not be only measured in the durability but the help that it provided to our ancestors, the things they were allowed to do once they dicovered how to mold it, and the tools that they produced and made many every day tasks easier for them and the ability of bronze to mantain the cutting edge longer than copper was one of the main reasons why it took its places in the fabrication of many tools.

4 0
4 years ago
A student wants to dissolve the maximum amount of CaF2 (Ksp = 3.2 x 10^−11) to make 1 L of aqueous solution.
Mekhanik [1.2K]

Answer:

The answer to A would be iv) 0.01 M HCL, but I'm not sure what the answer to part B is. Hope this helps.

Explanation:

7 0
3 years ago
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