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Drupady [299]
2 years ago
14

Helppppppppppppppppppppp

Chemistry
1 answer:
grandymaker [24]2 years ago
3 0

Answer:

Formation of sedimentary rocks

Explanation:

I believe this is correct, May I get a brainliest???

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The book procedure calls for 2,5-dimethylhexane-2,5-diol and concentrated hydrochloric acid to be shaken in a reaction vial. Whi
san4es73 [151]

Answer:

E) All of the above.

Explanation:

Hello,

Since the acidic nature of the HCl implies its corrosiveness, when it is in contact with the skin and eyes the burning starts immediately, so gloves and goggles must be worn. Next, the fuming hydrochloric acid (37% by mass) is volatile so it gives off even when dissolved into water, so it must be used in the fume hood. Then, since vapors are produced during the chemical reaction, an overpressure could be attained, that's why we must keep the glass sash of the fume hood between us and the vial. As a common risk, the vial could be dropped causing the hydrochloric acid to splash, so we must keep the vial well inside the hood.

Best regards.

7 0
3 years ago
The number of glyceraldehyde-3-phosphate molecules that would be produced from 24 turns of the calvin cycle would be
SVEN [57.7K]
The Calvin cycle, also called the light-independent or carbon fixation reactions, is the second stage of photosynthesis where water, and carbon dioxide (CO2) from air, are converted into organic compounds (i.e. sugars) using the energy from short-lived electronically excited carriers (ATP and NADPH) for the reactions. These organic compounds can then be used by the producing organism (i.e. plants) and the animals that feed on it. 

One product of the Calvin cycle is the glyceraldehyde-3-phosphate (G3P), which is later on used in the production of glucose and in the regeneration of <span>Ribulose 1,5-bisphosphate (RuBP), which is an organic compound</span> essential to the reactions in the cycle. 

One turn of Calvin Cycle produces 2 G3P molecules, each comprising of 3 carbons. This gives a total of 6 carbons. Five (5) of these carbons will be used to regenerate RuBP and only 1 will be available to form a surplus G3P later on. This surplus G3P will be used for the production of glucose (a 6-carbon sugar). 

Thus, 3 turns of the carbon cycle will produce 1 surplus G3P. There are 8 sets of 3-turns in 24 cycles, therefore, 

                       1 net G3P molecule * 8 sets of 3-turns  = 8 G3P molecules

Therefore, there are 8 net or surplus G3P molecules produced for 24 cycles of the Calvin Cycle. The total G3P molecules produced, including the ones that participated in the regeneration of RuBP would be 48 G3Ps. 

For every 3 turns, 6 G3P molecules are produced, 5 of which will be used in the regeneration of RuBP and 1 will be the net or surplus, to be used for the production of glucose. The 48 G3Ps then come from the calculation, 

                       6 total G3P molecules * 8 sets of 3-turns  = 48 G3P molecules


The figure below shows the products of the cycle after 3 turns (Source: https://ka-perseus-images.s3.amazonaws.com/2f4bdc8f8275834d3f5ef434d93bf16b991b2357.png). 

7 0
2 years ago
Describe how to determine the rate law for an<br> overall reaction that involves multiple steps.
Zarrin [17]

Answer:

The sum of each elementary step in a reaction mechanism must yield the overall reaction equation. From the rate law of the rate-determining step it  must agree with the experimentally determined rate law. The rate-determining step is the slowest step in a reaction mechanism. Because it is the slowest, it determines the rate of the overall reaction.

Explanation:

5 0
2 years ago
Might be hard to read but i do not understand what the “K” means.
alexdok [17]

it means kinetic energy

6 0
3 years ago
Read 2 more answers
Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coeffici
irina1246 [14]

Answer:

                     2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

Explanation:

Step 1: Write the unbalanced chemical equation,

                          C₄H₁₀ + O₂ → CO₂ + H₂O

Step 2: Balance Carbon  Atoms;

As there are 4 carbon  atoms on left hand side and 1 carbon atoms on right hand site therefore, to balance them multiply CO₂ on right hand side by 4 i.e.

                            C₄H₁₀ + O₂ → 4 CO₂ + H₂O

Step 3: Balance Hydrogen Atoms;

There are 10 hydrogen atoms on left hand side and 2 hydrogen atom on right hand site therefore, to balance them multiply H₂O on left hand side by 5 i.e.

                            C₄H₁₀ + O₂ → 4 CO₂ +  5 H₂O

Step 4: Balance Oxygen Atoms:

Now there are 2 oxygen atoms in reactant side and 13 in product side. So, multiply O₂ by 6.5 i.e.

                            C₄H₁₀ + 6.5 O₂ → 4 CO₂ + 5 H₂O

Step 5: Remove fraction coefficients as,

Multiply whole equation by 2 to get rid of fractions i.e.

                            2 C₄H₁₀ + 13 O₂ → 8 CO₂ + 10 H₂O

7 0
2 years ago
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