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Drupady [299]
3 years ago
14

Helppppppppppppppppppppp

Chemistry
1 answer:
grandymaker [24]3 years ago
3 0

Answer:

Formation of sedimentary rocks

Explanation:

I believe this is correct, May I get a brainliest???

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What is the mass of a sample of water that takes 2000 kJ of energy to boil into steam at 373 K. The latent heat of vaporization
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Answer:

\boxed{\text{889 g}}

Explanation:

The formula relating the mass m of a sample and the heat q to vaporize it is

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\begin{array}{rcl}2000 \times 10^{3} \text{ J} & = & m \times \dfrac{2.25 \times 10^{6} \text{ J}}{\text{1 kg}}\\\\m & = & \dfrac{2000 \times \times 10^{3}\text{ kg}}{2.25 \times 10^{6}}\\ & = & \text{0.889 kg}\\\\ & = & \text{889 g}\\\end{array}\\\text{The mass of water is $\boxed{\textbf{889 g}}$}

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3 years ago
Calculate the amount of grams of water that was used when 5525J of energy was used to boil this amount of water.
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Answer:

2.445 g

Explanation:

Step 1: Given and required data

  • Energy in the form of heat required to boil the water (Q): 5525 J
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  • Mass of water (m): ?

Step 2: Calculate the mass of water

We will use the following expression.

Q = ∆H°vap × m

m = Q / ∆H°vap

m = 5525 J / (2260 J/g)

m = 2.445 g

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