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liq [111]
3 years ago
14

Times for an ambulance to respond to a medical emergency in a certain town are normally distributed with a mean of 450 seconds a

nd a standard deviation of 50 seconds. Suppose there are 160 emergencies in that town.
In about how many emergencies are the response times expected between 400 seconds and 500 seconds?
a. 51b. 55c. 80d. 109
Mathematics
1 answer:
Gnoma [55]3 years ago
6 0

Answer:

(D)109

Step-by-step explanation:

Mean = 450 seconds

Standard deviation = 50

First, we determine the probability that the expected response time is between 400 seconds and 500 seconds, P(400<x<500)

Using the Z-Score,

P(\frac{x-\mu}{\sigma}

From the Z-Score table

P(-1<x<1) = 0.68269  

The probability that the expected response time is between 400 seconds and 500 seconds is 0.68269.

Since there are 160 Emergencies

Number whose expected time is between 400 seconds and 500 seconds

=160 X 0.68269 \approx 109

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The population decrease caused by the plague led to an economic depression. Merchants and tradespeople had fewer people to whom
tensa zangetsu [6.8K]

Answer:

Due to the high number of deaths and the subsequent population reduction, the merchants - and tradespeople in general - saw a decrease in the sales of their merchandise. Once the number of infected people by the plague reduced was reduced at the end of the Fifteenth Century, the population grew exponentially, thus creating a higher demand for services and goods.

7 0
2 years ago
If x and y are two supplementary angles whereas m
Rudiy27

Answer:

110degrees

Step-by-step explanation:

Complete question

Q4: If x and y are two supplementary angles whereas m<x=70 then find the m<y.

The sum of two supplementary angles is 180degrees, hence;

m<x + m<y = 180

70 + m<y = 180

m<y = 180 - 70

m<y = 110degrees

Hence the measure of ,=m<y is 110degrees

5 0
2 years ago
erik drove 439.92 miles on 15.6 gallons of gas. To the nearest hundredth, how many miles could he drive on 39.7 gallons of gas?
Thepotemich [5.8K]
In the question it is already given that Eric drove for 439.92 miles on 15.6 gallons. It is required to find the distance traveled on 39.7 gallons of gas. Also we have to find the answer to the nearest hundredth.
Then,
In 15.6 gallons Eric can drive for a distance = 439.92 miles
In 39.7 gallons Eric can drive for a distance = [(439.92/15.6) * 39.7] miles
                                                                       = 1119.54 miles
So the total distance traveled by Eric is 1120 miles with 39.7 gallons of gas. The answer has been calculated to the nearest hundredth.
6 0
3 years ago
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α = 8 per hour, so that the number o
Ksenya-84 [330]

Answer:

Step-by-step explanation:

Step1:

We have Suppose small aircraft arrive at a certain airport according to a Poisson process with rate α =8 per hour, so that the number of arrivals during a time period of t hours is a Poisson rv with parameter μ = 8t

Step2:

Let “X” the number of small aircraft that arrive during time t and it follows poisson distribution parameter “”

The probability mass function of poisson distribution is given by

P(X) = , x = 0,1,2,3,...,n.

Where, μ(mean of the poisson distribution)

a).

Given that time period t = 1hr.

Then,μ = 8t

             = 8(1)

             = 8

Now,

The probability that exactly 6 small aircraft arrive during a 1-hour period is given by

P(exactly 6 small aircraft arrive during a 1-hour period) = P(X = 6)

Consider,

P(X = 6) =  

              =  

              =  

              = 0.1219.

Therefore,The probability that exactly 6 small aircraft arrive during a 1-hour period is 0.1219.

1).P(At least 6) = P(X 6)

Consider,

P(X 6) = 1 - P(X5)

                = 1 - {+++++}

                = 1 - (){+++++}

                = 1 - (0.000335){+++++}

                = 1 - (0.000335){1+8+32+85.34+170.67+273.07}

                = 1 - (0.000335){570.08}

                = 1 - 0.1909

                = 0.8090.

Therefore, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8090.

2).P(At least 10) = P(X 10)

Consider,

P(X 10) = 1 - P(X9)

                 = 1 - {+++++

5 0
3 years ago
PLZ HELP!!!!
lozanna [386]

Answer:

(Q) Find the amount in the account at the end of 1 year.

(A) $8,190

2.

(Q) Find the amount in the account at the end of 2 years.

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3 years ago
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