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liq [111]
3 years ago
14

Times for an ambulance to respond to a medical emergency in a certain town are normally distributed with a mean of 450 seconds a

nd a standard deviation of 50 seconds. Suppose there are 160 emergencies in that town.
In about how many emergencies are the response times expected between 400 seconds and 500 seconds?
a. 51b. 55c. 80d. 109
Mathematics
1 answer:
Gnoma [55]3 years ago
6 0

Answer:

(D)109

Step-by-step explanation:

Mean = 450 seconds

Standard deviation = 50

First, we determine the probability that the expected response time is between 400 seconds and 500 seconds, P(400<x<500)

Using the Z-Score,

P(\frac{x-\mu}{\sigma}

From the Z-Score table

P(-1<x<1) = 0.68269  

The probability that the expected response time is between 400 seconds and 500 seconds is 0.68269.

Since there are 160 Emergencies

Number whose expected time is between 400 seconds and 500 seconds

=160 X 0.68269 \approx 109

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PLEASE HELP ME!<br> I have to find the measurement of the angle but i can't figure it out.
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<u>Answer:</u>

  • The value of ∠TMV is 45°.

<u>Step-by-step explanation:</u>

<u>We know that:</u>

  • ∠VTM + ∠TMV + ∠MVT = 180°
  • ∠VTM = 92
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<u>Work:</u>

  • ∠VTM + ∠TMV + ∠MVT = 180°
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