The oxidation number of oxygen in the carbonate ion found in malachite would be -2.
Molar mass NaCl = 58.44 g/mol
Therefore:
1 mole ---------- 58.44 g
? mole ---------- 72.70 g
72.70 x 1 / 58.44 => 1.244 moles of NaCl
Answer:
22.6 g
Explanation:
First we <u>use the PV=nRT equation</u>:
- R = 0.082 atm·L·mol⁻¹·K⁻¹
- T = 24 °C ⇒ 24 + 273.16 = 297.16 K
We <u>input the data</u>:
- 7.5 atm * 2.3 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 297.16 K
And <u>solve for n</u>:
Then we <u>convert 0.708 moles of oxygen gas (O₂) to grams</u>, using its <em>molar mass</em>:
- 0.708 mol * 32 g/mol = 22.6 g
Answer:
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Explanation: