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fenix001 [56]
3 years ago
8

In terms of impulse and conservation of momentum, explain why a glass is much more likely to break if it falls onto a cement flo

or than if it falls on to a carpeted floor.
Physics
1 answer:
Mashutka [201]3 years ago
3 0

Answer:

Explanation:

Glass is much more likely to break on the cement floor compared to the carpeted floor. In case of cement change in velocity occurs at a faster rate compared to the carpeted floor, so deceleration is more on the cemented floor.

As the Carpeted floor is not rigid so it takes more time to stop the glass that is why chances of breaking are less on the carpeted floor.    

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Hank eats many fatty foods. he doesn't exercise or wear sunscreen. hank is at risk for developing _____
IgorC [24]
High blood pressure
7 0
4 years ago
how much work must be done to accelerate an 8.5×10^5 kg train from a) 10m/s to 15m/s b) 15m/s to 20m/s and c) to an Initial stop
boyakko [2]
W = ΔE = 1/2 m (v₂ - v₁)²

W work
E kinetic energy
m mass
v₂ final velocity
v₁ initial velocity
7 0
3 years ago
What is the net force on a 4000 kg car that doubles its speed from 15 m/s to 30 m/s over 10 seconds
kozerog [31]

The net force  of the car <u>is 6000 N.</u>

Why?

To calculate the net force of the car during the given time, we first need to calculate its acceleration, and then, use Newton's Second Law equation to calculate the net force.

We can calculate the acceleration of the car during the given tieme using the following equation:

a=\frac{v-v_{o}}{time}

Substituting the given information, we have:

a=\frac{30\frac{m}{s} -15\frac{m}{s} }{10s}=\frac{15\frac{m}{s} }{10s}=1.5\frac{m}{s^{2} }

Now that we have calculated the acceleration, we can calculate the net force:

Force=mass*acceleration\\\\Force=4000kg*1.5\frac{m}{s^{2}}=6000\frac{kg.m}{s^{2}}=6000N

Hence, we have that the net force is equal to 6000N.

Have a nice day!

3 0
3 years ago
A 1500-nF capacitor with circular parallel plates 2.0 cm in diameter is accumulating charge at the rate of 40.0 mC/s at some ins
Delvig [45]

Answer:

B= 1.14 X 10^{-7} Tesla

Explanation:

B at point 7.0 cm radially outward is to find out?

Now for field strength in case of parallel plates in given as

        B=\frac{I\mu}{2r\pi}

        B=\frac{4\pi X 10^{-7} \frac{Tm}{A}X40 X10^{-3} \frac{C}{s}}{2X0.07mX\pi}

      B= 1.14 X 10^{-7} Tesla

For the second part as Capacitor is fully charged no more flow of current could take place hence

I= Current =o

so B = 0

6 0
3 years ago
A jet aircraft is traveling at 260 m/s in horizontal flight. The engine takes in air at a rate of 53.3 kg/s and burns fuel at a
IrinaVladis [17]

Answer:

The thrust of the jet engine is 4188.81 N.

Explanation:

Given that,

Speed = 260 m/s

Rate in air= 53.3 kg/s

Rate of fuel = 3.63 kg/s

Relative speed = 317 m/s

We need to calculate the rate of mass change in the rocket

Using formula of rate of mass

\dfrac{dM}{dt}=\dfrac{dM_{a}}{dt}+\dfrac{dM_{f}}{dt}

Put the value into the formula

\dfrac{dM}{dt}=53.3+3.63

\dfrac{dM}{dt}=56.93\ kg/s

We need to calculate the thrust of the jet engine

Using formula of thrust

T=\dfrac{dM}{dt}u-\dfrac{dM_{a}}{dt}v

Put the value into the formula

T=56.93\times317-53.3\times260

T=4188.81\ N

Hence, The thrust of the jet engine is 4188.81 N.

7 0
3 years ago
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