The grams of NaOH that are present in 247.0 ml of a 0.300M NaOH solution is 2.964 grams
<u><em>calculation</em></u>
Step 1: find moles of NaOH
moles = molarity x volume in liters
volume in liters = 247.0 /1000 = 0.247 liters
molarity = 0.300 M = 0.300 mol/l
moles = 0.300 mol/l x 0.247 =0.0741 moles
step 2: find mass of NaOH
mass= moles x molar mass
The molar mass of NaOH = 23 +1 +16= 40 g/mol
mass=0.0741 moles x40 g/mol =2.964 grams
