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3 years ago

How many grams of sodium hydroxide are present in 247.0 mL of a 0.300 M NaOH solution?

Chemistry

1 answer:

mamaluj [8]3 years ago

5 0

The grams of NaOH that are present in 247.0 ml of a 0.300M NaOH solution is 2.964 grams

calculation

Step 1: find moles of NaOH

moles = molarity x volume in liters

volume in liters = 247.0 /1000 = 0.247 liters

molarity = 0.300 M = 0.300 mol/l

moles = 0.300 mol/l x 0.247 =0.0741 moles

step 2: find mass of NaOH

mass= moles x molar mass

The molar mass of NaOH = 23 +1 +16= 40 g/mol

mass=0.0741 moles x40 g/mol =2.964 grams

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