Firstly, we will draw
RL series circuit
ET = 120 V, R = 40 Ω, and XL = 30 Ω
Firstly, we will find current

now, we can plug values
and we get

now, we can find voltage across L

so, we get

now, we can find absolute value



...............Answer
Answer:Simplifying
6 + -2x = 6x + -10x + 6
Reorder the terms:
6 + -2x = 6 + 6x + -10x
Combine like terms: 6x + -10x = -4x
6 + -2x = 6 + -4x
Add '-6' to each side of the equation.
6 + -6 + -2x = 6 + -6 + -4x
Combine like terms: 6 + -6 = 0
0 + -2x = 6 + -6 + -4x
-2x = 6 + -6 + -4x
Combine like terms: 6 + -6 = 0
-2x = 0 + -4x
-2x = -4x
Solving
-2x = -4x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '4x' to each side of the equation.
-2x + 4x = -4x + 4x
Combine like terms: -2x + 4x = 2x
2x = -4x + 4x
Combine like terms: -4x + 4x = 0
2x = 0
Divide each side by '2'.
x = 0
Simplifying
x = 0
Step-by-step explanation:
Answer:
angle DLM= 21+50=71 degrees i think
Step-by-step explanation:
take the 2 from 2x and divide 42 by the 2 and you have your variable x solved
Answer:
(f(x, y, z), g(x, y, z), h(x, y, z))
Step-by-step explanation:
i think it is amswer
Answer:
Unbounded, infinite number of solutions
Step-by-step explanation:
1. Graph each inequality separately
2. Choose test point to determine which side of line needs to be shaded
3. The solution will be the the area where the shadings from both inequalities overlap
Since, the overlap almost covers the 2nd and 3rd quadrants there are an infintite number of solutions