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dedylja [7]
3 years ago
15

Will mark Brianliest answer correctly !!!!!!!!!! Pleaseeee helpppp !!!!!!!!!!!!!!!!!

Mathematics
2 answers:
zavuch27 [327]3 years ago
7 0
It would be 2 Square root 10

german3 years ago
6 0
2 is the square root of 10
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In a series RL circuit, ET = 120 V, R = 40 Ω, and XL = 30 Ω. How much is EL?
dezoksy [38]

Firstly, we will draw

RL series circuit

ET = 120 V, R = 40 Ω, and XL = 30 Ω

Firstly, we will find current

I=\frac{E_T}{R+jX_L}

now, we can plug values

and we get

I=\frac{120}{40+j30}

now, we can find voltage across L

E_L=IjX_L

so, we get

E_L=\frac{120}{40+j30}(j30)

now, we can find absolute value

|E_L|=120\frac{30}{\sqrt{40^2+30^2}  }

|E_L|=120\frac{30}{ 50 }

|E_L|=120\frac{3}{ 5 }

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2 years ago
6 - 2x = 6x = 10 + 6
Natalija [7]

Answer:Simplifying

6 + -2x = 6x + -10x + 6

Reorder the terms:

6 + -2x = 6 + 6x + -10x

Combine like terms: 6x + -10x = -4x

6 + -2x = 6 + -4x

Add '-6' to each side of the equation.

6 + -6 + -2x = 6 + -6 + -4x

Combine like terms: 6 + -6 = 0

0 + -2x = 6 + -6 + -4x

-2x = 6 + -6 + -4x

Combine like terms: 6 + -6 = 0

-2x = 0 + -4x

-2x = -4x

Solving

-2x = -4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4x' to each side of the equation.

-2x + 4x = -4x + 4x

Combine like terms: -2x + 4x = 2x

2x = -4x + 4x

Combine like terms: -4x + 4x = 0

2x = 0

Divide each side by '2'.

x = 0

Simplifying

x = 0

Step-by-step explanation:

3 0
3 years ago
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GEOMETRY - I NEED HELP!!!
Ainat [17]

Answer:

angle DLM= 21+50=71 degrees i think

Step-by-step explanation:

take the 2 from 2x and divide 42 by the 2 and you have your variable x solved

3 0
2 years ago
The position (resp. velocity, resp. acceleration) at time t of a particle of mass m is c(t) (resp. v(t), resp. a(t)). Let F(x, y
sergey [27]

Answer:

(f(x, y, z), g(x, y, z), h(x, y, z))

Step-by-step explanation:

i think it is amswer

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2 years ago
У — 3x 4<br> у &gt; 4х +1<br><br> Anyone know the answe on how to solve this???
Katen [24]

Answer:

Unbounded, infinite number of solutions

Step-by-step explanation:

1. Graph each inequality separately

2. Choose test point to determine which side of line needs to be shaded

3. The solution will be the the area where the shadings from both inequalities overlap

Since, the overlap almost covers the 2nd and 3rd quadrants there are an infintite number of solutions

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2 years ago
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