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3 years ago

I have a project due in 3 days and I need help!

1 answer:

8 0

1.Phases - Gas, liquid and solid. Gas, liquid, and solid are known as the three states of matter or material, but each of solid and liquid states may exist in one or more forms.

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What equations would you use to find force?

Klio2033 [76]

Answer:

F = m x a

Explanation:

F = force

m = mass of an object

a = acceleration

6 0

3 years ago

PLS HELP WITH THIS FOR BRAINLIST IF ITS RIGHT

Zolol [24]

Answer:

the first one is Primary

the second one I think it's Mature but I don't know

5 0

3 years ago

A dipole of moment 0.5 e·nm is placed in a uniform electric field with a magnitude of 8 times 104 N/C. What is the magnitude of

Over [174]

Answer:

The net torque is zero

Explanation:

Let's assume that the dipole is compose of two equal but oposite charges e, and it cam be represented by a rod with one end having a charge e and the other end with a charge of -e. Notice that the dipole is parallel to the electric field thus the force felt by both of the charges will be parallel to the electric field. This means that there will be no components of the forces that are perpendicular to the rod which is a requirement for it to have a torque.

8 0

3 years ago

A meter stick hurtles through space at a speed of 0. 95c relative to you, with its length perpendicular to the direction of moti

marta [7]

Answer:

Explanation:

Caty , Use the relativity formula for length. ( they teach this in H.S. ? ) it's from my Modern Physics in college, A 300 level class

L = $L_{0}$ $\sqrt{1-\frac{v^{2} }{c^{2} } }$

L = 3 $\sqrt{1-\frac{.95^{2} }{1^{2} } }$

L = 0.9367496998 meters

L = 0.94 meters approx

6 0

2 years ago

A 16 pound weight attached to a spring exhibits simple harmonic motion. Determine the equation of motion if the spring constant

yarga [219]

Answer:

T = 2.82π s

x = Acos(0.71t)

Explanation:

This problem can be solved by using the expressions

$T = 2\pi \sqrt{\frac{m}{k} }$ ( 1 )

$x=Acos(\omega t) = Acos(\frac{2\pi }{T}t )$ ( 2 )

where T is the period of oscillation of the system, m is the mass of the object attached to the spring, k is the spring constant and x is the position of the object.

By replacing in the expression (1):

$T=2\pi \sqrt{\frac{16 lb}{8lb/ft}} = 2.82\pi s$

Taking 6 inches as the amplitude of the motion, we have

$x=6cos(\frac{2\pi }{2.82\pi }t ) = 6cos(0.71t)$

I hope this is useful for you

Regards

8 0

3 years ago