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Tju [1.3M]
3 years ago
14

Find the final pressure of gas at 150k. If the pressure of the gas is 210 kPa at 120 K.

Chemistry
1 answer:
katrin [286]3 years ago
4 0
Since the volume is constant,
p1/t = p2/ t
210/120 = p2/150
p2= 262.5kpa
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Inclined planes reduce the amount of effort needed to move an object, but increases
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Inclined planes reduce the amount of effort needed to move an object, but increases the length of the ramp.

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Mechanical advantage is the measure of amount of effort needed to move an object. The mechanical advantage can be calculated as the ratio of length of ramp to the height of ramp for an inclined plane.

As it is known that an object can be easily moved on an inclined plane than on a vertical plane, this is because, the inclined plane provides greater output force. But in that case, the effort required will be reduced with the cost of increasing the distance of the movement of object.

In other terms , the ramp's length of inclined planes has to get increased in order to reduce the amount of effort needed to move an object. This is because as the mechanical advantage has length of the ramp in the numerator, with the increase in numerator value or length value the mechanical advantage will also increase.

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How many orbitals are available in a “d” orbital configuration?
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e.)5

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What did Thomas Young, Max planck and Albert Einstein contribute towards the nature of light?
Lera25 [3.4K]

The contribution to the nature of light-

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Thomas Young proposed the most important double-slit experiment which shows that light acts like a wave and shows the pattern of interferences.

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Albert Einstein proposed the quantum theory of light. He determined that light exists in discrete quanta of energy called photons.

To learn more about the nature of light, visit: brainly.com/question/4423091

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5 0
1 year ago
If the initial velocity of the car in the previous problem (the car accelerates at 5.00 km/hr/s for 3.50 sec) is 22.6 km/hr, wha
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The solubility of NaCH3CO2 in water is ~1.23 g/mL. What would be the best method for preparing a supersaturated NaCH3CO2 solutio
Len [333]

Answer:

b) add 130 g of NaCH₃CO₂ to 100 mL of H₂O at 80 °C while stirring until all the solid dissolves, then let the solution cool to room temperature.

Explanation:

The solubility of NaCH₃CO₂ in water is ~1.23 g/mL. This means that at room temperature, we can dissolve 1.23 g of solute in 1 mL of water (solvent).

<em>What would be the best method for preparing a supersaturated NaCH₃CO₂ solution?</em>

<em>a) add 130 g of NaCH₃CO₂ to 100 mL of H₂O at room temperature while stirring until all the solid dissolves.</em> NO. At room temperature, in 100 mL of H₂O can only be dissolved 123 g of solute. If we add 130 g of solute, 123 g will dissolve and the rest (7 g) will precipitate. The resulting solution will be saturated.

<em>b) add 130 g of NaCH₃CO₂ to 100 mL of H₂O at 80 °C while stirring until all the solid dissolves, then let the solution cool to room temperature. </em>YES. The solubility of NaCH₃CO₂ at 80 °C is ~1.50g/mL. If we add 130 g of solute at 80 °C and let it slowly cool (and without any perturbation), the resulting solution at room temperature will be supersaturated.

<em>c) add 1.23 g of NaCH₃CO₂ to 200 mL of H₂O at 80 °C while stirring until all the solid dissolves, then let the solution cool to room temperature.</em> NO. If we add 1.23 g of solute to 200 mL of water, the resulting solution will have a concentration of 1.23 g/200 mL = 0.00615 g/mL, which represents an unsaturated solution.

5 0
3 years ago
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