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Komok [63]
3 years ago
14

Please answerrrrrrrrrrrrrrrrrrrrrrrrr

Chemistry
1 answer:
nydimaria [60]3 years ago
8 0

Answer: I'm in no way like an expert but I've heard water goes from an elevated area to a lower area. So it should be arrows that start at a more elevated to less elevated. Like white to brown, and orange to yellow, and stuff like that. I hope that helped? Anyway, have a lovely day!

Explanation:

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8.43g of CaCl2·2H2O is dissolved in 40.0g of H2O. What is the molality of the solution? (Note that the H2O in the CaCl2·2H2O mus
lara31 [8.8K]

Answer:

[CaCl₂·2H₂O] = 1.43 m

Explanation:

Molality is mol of solute / kg of solvent.

Mass of solvent = 40 g

Let's convert g to kg → 40 g / 1000 = 0.04 kg

Let's determine the moles of solute (mass / molar mass)

8.43 g / 146.98 g/mol = 0.057 mol

Molality = 0.057 mol / 0.04 kg → 1.43

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3 years ago
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What is the volume of a gas if 0.182 moles of the gas is at 1.99 atm and 83.4oC?
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Answer:

2,67 L

Explanation:

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2 years ago
A bomb calorimeter has a heat capacity of 783 J/oC and contains 254 g of water whose specific heat capacity is 4.184 J/goC. How
IrinaK [193]

Answer : The amount of heat evolved by a reaction is, 4.81 kJ

Explanation :

Heat released by the reaction = Heat absorbed by the calorimeter + Heat absorbed by the water

q=[q_1+q_2]

q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]

where,

q = heat released by the reaction

q_1 = heat absorbed by the calorimeter

q_2 = heat absorbed by the water

c_1 = specific heat of calorimeter = 783J/^oC

c_2 = specific heat of water = 4.184J/g^oC

m_2 = mass of water = 254 g

\Delta T = change in temperature = T_2-T_1=(23.73-26.01)=-2.28^oC

Now put all the given values in the above formula, we get:

q=[(783J/^oC\times -2.28^oC)+(254g\times 4.184J/g^oC\times -2.28^oC)]

q=-4208.28J=-4.81kJ

Therefore, the amount of heat evolved by a reaction is, 4.81 kJ

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3 years ago
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The maximum oxygen uptake is known as the VO2 max.
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What types of elements form covalent bonds?
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Covalent bonds form when electrons are shared between two nonmetals.
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