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Vesnalui [34]
3 years ago
5

Which products are formed when aluminum is added to a silver chloride solution? Use the activity series below if needed. Al>

Mn > Zn>.Cr > Fe > Cd> Co > Ni > Sn > Pb>H> Sb > Bi > Cu> Ag > Pd >Hg > Pt O none O only AICI3 O AlCl3 and Ag O AIAg3 and Cl2​
Chemistry
2 answers:
kap26 [50]3 years ago
8 0

Answer:

AlCl3 and Ag

Explanation:

Edge 2020

horrorfan [7]3 years ago
8 0

the answer is c just did the test

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How many atoms are there in 5.00 mol of sulphur (S)?
Mumz [18]

Answer:

3.01 × 10²⁴ atoms S

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

5.00 mol S

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

<u />5.00 \ mol \ S(\frac{6.022 \cdot 10^{23} \ atoms \ S}{1 \ mol \ S} ) = 3.011 × 10²⁴ atoms S

<u />

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

3.011 × 10²⁴ atoms S ≈ 3.01 × 10²⁴ atoms S

6 0
3 years ago
What is the PH of a 7.5x10^-3 M OH solution
Triss [41]
pH: 11.8750612634
pOH: 2.12493873661
[H+]: 1.33333333333E-12
[OH-]: 0.0075
BASE
5 0
3 years ago
Read 2 more answers
Which number represents an acidic pH, 4 or 9? _______ Numerical Answers Expected! Answer for Blank 1:
Tasya [4]

Answer:

4

Explanation:

pH scale of acidic is 4.

8 0
3 years ago
Mrs. Nogaki tested four black markers in rubbing alcohol and in water. Each filter paper had four evenly spaced dots. She found
ExtremeBDS [4]

Answer:

Lost pigment of marker when dipped in alcohol

Explanation:

dependent viable = output

so it's the output of what happens after the input.

  • she put the marker in the water which is the independent variable, that's the input
  • the output or the result of that decision is having lost pigment in the marker

8 0
2 years ago
1 -Is Apple Juice with No Pulp a pure substance or a mixture ?
-Dominant- [34]

1. Pure substance

2.mixture

4 0
3 years ago
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