All categories

3 years ago

Type the correct answer in the box.

Chemistry

1 answer:

Murljashka [212]3 years ago

8 0

Answer:

a= In scientific notation

6.96×10⁵ Km

b =In expanded notation

0.00019 mm

Explanation:

Given data:

Radius of sun = 696000 Km

size of bacterial cell = 1.9 ×10⁻⁴ mm

Radius of sun in scientific notation = ?

Size of bacterial cell in expanded notation = ?

Solution:

Radius of sun:

696000 Km

In scientific notation

6.96×10⁵ Km

Size of bacterial cell:

1.9 ×10⁻⁴ mm

In expanded notation

1.9/ 10000 = 0.00019 mm

You might be interested in

This formula equation is unbalanced.

viktelen [127]

answer is: coefficient is 2.

8 0

3 years ago

What the correct answer?

alexandr402 [8]

B. Bleach and sea water should be identified as bases

Explanation:

The pH scale measures the acidic or basic nature of a substance.
Ranges from 0 to 14.
If pH is lower than 7 → the solution is an acid.
If pH is more than 7 → the solution is an basic or alkaline.
If a pH is a 7 it is neutral.

In the given question, the pH scale measures for bleach is 8 and for sea water it is 13. So, bleach is basic, not neutral and Sea water is basic too instead of acid. So, Bleach and sea water should be identified as bases.

3 0

3 years ago

Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh

Dima020 [189]

Answer: The $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

Explanation:

For the given chemical reaction:

$2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)$

Half reactions for the given cell follows:

Oxidation half reaction: $ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V$ ( × 2)

Reduction half reaction: $Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=1.36-(0.954)=0.406V$

To calculate standard Gibbs free energy, we use the equation:

$\Delta G^o=-nFE^o_{cell}$

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

$E^o_{cell}$ = standard cell potential = 0.406 V

Putting values in above equation, we get:

$\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J$

Hence, the $\Delta G^o$ for the given reaction is $-7.84\times 10^4J$

4 0

3 years ago

Compare la configuración realizada con la que aparece en la tabla periódica y confirma si esta en

mart [117]

Answer:

Explanation:

4 0

3 years ago

Can someone help me? I will give BRAINLIEST

Mkey [24]

Troposphere is the highest layer of the atmosphere and touches space

Startophere is where stratus clouds form up high in the sky

The Mesosphere is the third layer you need to know and it’s low density ...yo?

Thermosphere we’re getting closer and closer to earth

Exoshpere were airplanes are high, buckle up it’s time to fly

4 0

3 years ago

Read 2 more answers