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White raven [17]

3 years ago

9

which of the following statements about perpendicular lines is true? a. perpendicular lines have a constant distance between the

m. b. perpendicular lines intersect at a 90 degrees angle. c. there is no standard symbol for perpendicular lines. d. perpendicular lines do not exist in the same plane.

1 answer:

Flauer [41]3 years ago

7 0

B is the right answer

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Can someone PLEASE answer this and explain I really need help I’ll mark brainliest

svetlana [45]

Answer:

Michael = x÷7

lee = 2(x÷7)

(x÷7)+2(x÷7)

Step-by-step explanation:

since he earns x dollars every seven days, to get the amount he earns, you divide that amount by 7 and for Lee, she gets twice as much so you multiply Michael's amount by 2

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2 years ago

PLEASE HELP ME QUICK!!!20 POINTS!!!!!!!!

Blizzard [7]

the volume scales by (1/10)^3. so it would be 48.875*10^-3.

5 0

3 years ago

This table models a linear function. x −8 −4 4 8 y −3 0 6 9 Enter the coordinates of the y-intercept in the boxes.

adell [148]

Answer:

y-intercept is 3

Step-by-step explanation:

We are given table

x: -8 -4 4 8

y: -3 0 6 9

We can select any two points

$x_1=-8,y_1=-3$

$x_2=-4,y_2=0$

Firstly, we will find slope

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug values

$m=\frac{0+3}{-4+8}$

$m=\frac{3}{4}\quad$

now, we can use point slope form of line

$y-y_1=m(x-x_1)$

we can plug values

$y+3=\frac{3}{4}(x+8)$

now, we can solve for y

$y=\frac{3}{4}x+3$

For finding y-intercept , we can plug x=0

$y=\frac{3}{4}\times 0+3$

$y=0+3$

$y=3$

So,

y-intercept is 3

8 0

3 years ago

The Identity function i behaves just like the number 1. That is (F o i)=f and (i o g)= g

andrezito [222]

I'll denote the identity function by $\mathrm{Id}$ . Then for any functions $f$ with inverse $f^{-1}$ ,

$\begin{cases}f\circ\mathrm{Id}=f\\\mathrm{Id}\circ f=f\\f\circ f^{-1}=\mathrm{Id}\end{cases}$

One important fact is that composition is associative, meaning for functions $f,g,h$ , we have

$(f\circ g)\circ h=f\circ(g\circ h)$

So given

$h=f\circ g$

we can compose the functions on either side with $g^{-1}$ :

$h\circ g^{-1}=(f\circ g)\circ g^{-1}=f\circ(g\circ g^{-1})$

then apply the rules listed above:

$h\circ g^{-1}=f\circ\mathrm{Id}=f$

3 0

2 years ago

ASAP<br><br> What is the distance between (6, 2) and (-3, -2)?<br> 9<br> 3<br> 5

butalik [34]

The distance between the points (6,2) and (-3,-2) is A) 9 units.

8 0

3 years ago