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STatiana [176]
3 years ago
14

21 Given the following acid dissociation constants, which acid has the strongest conjugate base?

Chemistry
1 answer:
Makovka662 [10]3 years ago
7 0
The correct answer is HCN.
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How would male become female?
bekas [8.4K]

Answer:

Well unless you have your testicales removed but I don't really know

6 0
3 years ago
Californium-252 is bombarded with a boron-10 nucleus to produce another nuclide and six neutrons. what nuclide forms?
Yanka [14]

Answer: the nuclide is lawrencium-103


Using the isotopes notation it can be written as ²⁵⁶ ₁₀₃ Lr.


The number 256 is a superscript to the left of the symbol of the element (Lr) and the number 103 is a subscript to the left of the symbol


Explanation:


1) To determine the nuclide formed you have to rely in a mass and particles balance.


2) californium - 252 is the isotope has mass number 252, atomic number 98 (you obtain this information in a periodic table, remember that it is the number of protons).


The number of neutrons is determined from the formula


mass number = atomic number + number of neutrons ⇒ number of neutrons = mass number - atomic number


∴252 - 98 = 154 neutrons


3) boron - 10 nucleus has mass number 10, and atomic number 5 (from periodic table)


⇒ number of neutrons = 10 - 5 = 5.


4) Now the mass balance leads to:


mass number of californium-252 + mass number of boron-10 = unknown mass number + mass number of mass number of 6 neutrons


⇒ 252 + 10 = x + 6 ⇒ x = 252 + 10 - 6 = 256


5) Since neutrons do not change the atomic masses, number of protons, you can do this balance based on the atomic numbers (i.e. the same that number of protons):


atomic number of californium-252 + atomic number of boron - 10 = unknown atomic number


98 + 5 = A


A = 103


The element with atomic number 103 is lawrencium (Lr)


Calculate the number of neutrons: mass number - atomic number = 256 - 103 = 153.


Therefore, the new isotope is lawrencium (Lr) whith 153 neutrons.


Using the notation for isotopes the equation that show the reaction is:


²⁵² ₉₈ Cf + ¹⁰ ₅ B → ²⁵⁶ ₁₀₃ Lr + 6 ¹₀n

5 0
3 years ago
Read 2 more answers
Use the drop-down menus to match the type of intermolecular force to its name.
geniusboy [140]

Answer:

Dipole-dipole interactions : occur between polar molecules

Dipole-induced dipole interactions: occur between polar and nonpolar molecules

London dispersion forces: occur in all substances, but are the most important in nonpolar substances

Hydrogen bond: electrostactic attraction between a hydrogen atom and a highly electronegative atom

van der Waals forces: electrostatic interactions between partially charged regions of a molecule

3 0
3 years ago
Read 2 more answers
A student titrated a solution containing 3.7066 g of an unknown Diprotic acid to the end point using 28.94 ml of 0.3021 M KOH so
uranmaximum [27]

Answer:

<u>Molar</u><u> </u><u>mass</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>diprotic</u><u> </u><u>acid</u><u> </u><u>is</u><u> </u><u>4</u><u>2</u><u>4</u><u> </u><u>grams</u>

Explanation:

[hint: <u>diprotic</u><u> </u><u>acid</u><u> </u><u>only</u><u> </u><u>contains</u><u> </u><u>2</u><u> </u><u>hydrogen</u><u> </u><u>protons</u><u>]</u>

Ionic equation:

{ \bf{2OH { }^{ - }  _{(aq)} + 2H { }^{ + } _{(aq)}→  2H _{2} O _{(l)} }}

first, we get moles of potassium hydroxide in 28.94 ml :

{ \sf{1 \: l \: of \: KOH \: contains \: 0.3021 \: moles}} \\ { \sf{0.02894 \: l \: of \: KOH \: contain \: (0.02894 \times 0.3021) \: moles}} \\ { \underline{ = 0.008743 \: moles}}

since mole ratio of diprotic acid : base is 2 : 2, moles are the same.

Therefore, <u>m</u><u>o</u><u>l</u><u>e</u><u>s</u><u> </u><u>o</u><u>f</u><u> </u><u>a</u><u>c</u><u>i</u><u>d</u><u> </u><u>t</u><u>h</u><u>a</u><u>t</u><u> </u><u>r</u><u>e</u><u>a</u><u>c</u><u>t</u><u>e</u><u>d</u><u> </u><u>a</u><u>r</u><u>e</u><u> </u><u>0</u><u>.</u><u>0</u><u>0</u><u>8</u><u>7</u><u>4</u><u>3</u><u> </u><u>m</u><u>o</u><u>l</u><u>e</u><u>s</u><u>.</u>

{ \sf{0.008743 \: moles \: of \: acid \: weigh \: 3.7066 \: g}} \\ { \sf{1 \: mole \: of \: acid \: weighs \: ( \frac{1 \times 3.7066}{0.008743}) \: g }} \\  = { \underline{423.95 \: g \approx424 \: grams}}

for the molar mass:

8 0
3 years ago
1. look at the sequence of pictures what happened to the Apple overtime. 2. no chemical was added to the Apple explain why the A
Goshia [24]

Answer: it started too rot over time mold over time and decay and if you cooked a apple it would melt like ice cream cause of the heat waves and if the apple is surrounded by air i think what would happen it would still rot I guess but i wouldnt know for sure cause things with air take time too rot and things with air rot faster and slicing the apple into more pieces would make it decay or rot or mold faster cause its open and accepting everything it sees like bacteria bugs all that

Explanation: like the longer a apple is left half open it starts too rot then mold over time getting all bad and not good too eat or decay

read it all the stuff is in there i think

8 0
3 years ago
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