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2 years ago

14

Water has a molar mass of 18.0 g/mol. How many particles of water do you drink if you drink 64 oz., or 1893 grams, of water in a

day?

1 answer:

umka21 [38]2 years ago

4 0

Answer:

$\frac{1839}{18} = 102.16$

Take 102.16 and multiply by avogadros #

and you get 6.33 × 10^25 otherwise A

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(b) on the graph above, carefully draw three curves, one for each of the three gases, starting from the initial point you drew i

borishaifa [10]

Obg statement aka the unkownExplanation:

8 0

3 years ago

Carbonyl fluoride, COF2, is an important intermediate used in the production of fluorine-containing compounds. For instance, it

Sauron [17]

Answer:

The concentration of COF₂ at equilibrium is 0.296 M.

Explanation:

To solve this equilibrium problem we use an ICE Table. In this table, we recognize 3 stages: Initial(I), Change(C) and Equilibrium(E). In each row we record the <em>concentrations</em> or <em>changes in concentration</em> in that stage. For this reaction:

2 COF₂(g) ⇌ CO₂(g) + CF₄(g)

I 2.00 0 0

C -2x +x +x

E 2.00 - 2x x x

Then, we replace these equilibrium concentrations in the Kc expression, and solve for "x".

$Kc=8.30=\frac{[CO_{2}] \times [CF_{4}] }{[COF_{2}]^{2} } =\frac{x^{2} }{(2.00-2x)^{2} } \\8.30=(\frac{x}{2.00-2x} )^{2} \\\sqrt{8.30} =\frac{x}{2.00-2x}\\5.76-5.76x=x\\x=0.852$

The concentration of COF₂ at equilibrium is 2.00 -2x = 2.00 - 2 × 0.852 = 0.296 M

6 0

3 years ago

A 100 W light bulb is placed in a cylinder equipped with a moveable piston. The light bulb is turned on for 2.0×10−2 hour, and t

drek231 [11]

Answer:

(a) ΔU = 7.2x10²

(b) W = -5.1x10²

(c) q = 5.2x10²

Explanation:

From the definition of power (p), we have:

$p = \frac {\Delta W}{\Delta t} = \frac {\Delta U}{\Delta t}$ (1)

<em>where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s) </em>

(a) We can calculate the energy (ΔU) using equation (1):

$\Delta U = p \cdot \Delta t = 100 \frac{J}{s} \cdot 2.0\cdot 10^{-2} h \cdot \frac{3600s}{1h} = 7.2 \cdot 10^{2} J$

(b) The work is related to pressure and volume by:

$\Delta W = -p \Delta V$

<em>where p: pressure and ΔV: change in volume = V final - V initial </em>

$\Delta W = - p \cdot (V_{fin} - V_{ini}) = - 1.0 atm (5.88L - 0.85L) = - 5.03 L \cdot atm \cdot \frac{101.33J}{1 L\cdot atm} = -5.1 \cdot 10^{2} J$

(c) By the definition of Energy, we can calculate q:

$\Delta U = \Delta W + \Delta q$

<em>where Δq: is the heat transfer </em>

$\Delta q = \Delta U - \Delta W = 7.2 J - (-5.1 \cdot 10^{2} J) = 5.2 \cdot 10^{2} J$

I hope it helps you!

6 0

3 years ago

Examine the given reaction. NH4NO3(s) → NH4+(aq) + NO3–(aq) ΔH° = 25.45 kJ/mol ΔS° = 108.7 J/mol·K Which of the given is correct

kobusy [5.1K]

Answer:

B)−6,942 J /mol

Explanation:

At constant temperature and pressure, you cand define the change in Gibbs free energy, ΔG, as:

ΔG = ΔH - TΔS

Where ΔH is enthalpy, T absolute temperature and ΔS change in entropy.

Replacing (25°C = 273 + 25 = 298K; 25.45kJ/mol = 25450J/mol):

ΔG = ΔH - TΔS

ΔG = 25450J/mol - 298K×108.7J/molK

ΔG = -6942.6J/mol

Right solution is:

<h3>B)−6,942 J /mol</h3>

8 0

3 years ago

Which is the frequency of the wave shown?

ratelena [41]

Answer:

The frequency of wave is 0.125 Hz.

Explanation:

Frequency:

"It is an event repeat itself in a given period of time"

The unit of frequency is the Hz . If time is measured in seconds then frequency will be in Hz. Hz is equal to the per second.

Formula:

f = 1/ T

f = 1/ 8 sec

f = 0.125 Hz

5 0

3 years ago