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Nastasia [14]
2 years ago
14

Water has a molar mass of 18.0 g/mol. How many particles of water do you drink if you drink 64 oz., or 1893 grams, of water in a

day?

Chemistry
1 answer:
umka21 [38]2 years ago
4 0

Answer:

\frac{1839}{18}  = 102.16

Take 102.16 and multiply by avogadros #

and you get 6.33 × 10^25 otherwise A

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Draw the most stable resonance structure for the intermediate in the electrophilic aromatic bromination of aniline, anisole, and
ASHA 777 [7]

Answer:

Here's what I get

Explanation:

(a) Intermediates

The three structures below represent one contributor to the resonance-stabilized intermediate, in which the lone pair electrons on the heteroatom are participating (the + charge on the heteroatoms do not show up very well).

(b) Relative Stabilities

The relative stabilities decrease in the order shown.

N is more basic than O, so NH₂ is the best electron donating group (EDG) and will best stabilize the positive charge in the ring. However, the lone pair electrons on the N in acetanilide are also involved in resonance with the carbonyl group, so they are not as available for stabilization of the ring.

(c) Relative reactivities

The relative reactivities would be

C₆H₅-NH₂ >  C₆H₅-OCH₃ > C₆H₅-NHCOCH₃

4 0
2 years ago
How many grams of chromium metal are plated out when a constant current of 8.00 A is passed through an aqueous solution containi
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Explanation:

6 0
2 years ago
Explain what each quantum number in a quantum number set tells you about the electron. Compare and contrast the locations and pr
klio [65]
This is a bit long right now.

(n l m s) these are the numbers.

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Complete the sentences to explain your reasoning.
tangare [24]

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I need the columns to do the question

Explanation:

3 0
2 years ago
How many grams of NaCl (molecular weight = 58.4 g mole-1) would you dissolve in water to make a total volume of 500 mL of soluti
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Given :

Volume , V = 500 mL .

Molarity , M = 0.5 M .

Molecular mass of NaCl is 58.4\ g/mole .

To Find :

How many grams of NaCl is required .

Solution :

Let , NaCl required is x gram .

Molarity is given by :

M=\dfrac{\text{Number of moles}}{\text{Volume (in liters) }}\\\\M=\dfrac{m}{M\times V}\\\\0.5=\dfrac{x}{58.4\times 0.5}\\\\x=0.5^2\times 58.4\ g\\\\x=14.6\ g

Hence , this is the required solution.

6 0
2 years ago
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